有没有办法让平行坐标一直到边缘,然后在它之间平均间隔“尺寸”?我认为x = d3.scaleBand().rangeRound([0, width]).padding(1)
是罪魁祸首,但似乎还有其他东西在起作用。如果有人帮助我,我真的很感激。
var margin = {top: 20, right: 10, bottom: 10, left: 20},
width = d3.select(ele[0])._groups[0][0].offsetWidth - margin.left - margin.right,
height = 400 - margin.top - margin.bottom;
// set the height based on the calculations above
svg.attr('height', height + margin.top + margin.bottom);
var x = d3.scaleBand().rangeRound([0, width]).padding(1),
y = {},
dragging = {},
selected;
var line = d3.line(),
background,
foreground,
extents;
x.domain(dimensions = d3.keys(data[0]).filter(function(d) {
if(d === "name") {
return false;
}
return y[d] = d3.scaleLinear()
.domain(d3.extent(data, function(p) {
return +p[d]; }))
.range([height, 0]);
}));
extents = dimensions.map(function(p) { return [0,0]; });
// Add grey background lines for context.
background = svg.append("g")
.attr("class", "background")
.attr("transform", "translate(0," + margin.top + ")")
.selectAll("path")
.data(data)
.enter().append("path")
.attr("d", path);
// Add blue foreground lines for focus.
foreground = svg.append("g")
.attr("class", "foreground")
.attr("transform", "translate(0," + margin.top + ")")
.selectAll("path")
.data(data)
.enter().append("path")
.attr("d", path);
// Add a group element for each dimension.
var g = svg.selectAll(".dimension")
.data(dimensions)
.enter().append("g")
.attr("class", "dimension")
.attr("transform", function(d) { return "translate(" + x(d) + ")"; })
.call(d3.drag()
.subject(function(d) { return {x: x(d)}; })
.on("start", function(d) {
dragging[d] = x(d);
background.attr("visibility", "hidden");
})
.on("drag", function(d) {
dragging[d] = Math.min(width, Math.max(0, d3.event.x));
foreground.attr("d", path);
dimensions.sort(function(a, b) { return position(a) - position(b); });
x.domain(dimensions);
g.attr("transform", function(d) { return "translate(" + position(d) + ")"; })
})
.on("end", function(d) {
delete dragging[d];
transition(d3.select(this)).attr("transform", "translate(" + x(d) + ")");
transition(foreground).attr("d", path);
background
.attr("d", path)
.transition()
.delay(500)
.duration(0)
.attr("visibility", null);
}));
// Add an axis and title.
g.append("g")
.attr("class", "y axis")
.each(function(d) { d3.select(this).call(d3.axisLeft(y[d]));})
.attr("transform", "translate(0," + margin.top + ")")
.append("text")
.style("text-anchor", "middle")
.attr("y", -9)
.text(function(d) { return d; });
// Add and store a brush for each axis.
g.append("g")
.attr("class", "brush")
.attr("transform", "translate(0," + margin.top + ")")
.each(function(d) {
d3.select(this)
.call(y[d].brush = d3.brushY().extent([[-8, 0], [8,height]])
.on("brush start", brushstart)
.on("brush", brush_parallel_chart));
})
.selectAll("rect")
.attr("x", -8)
.attr("width", 16);
function position(d) {
var v = dragging[d];
return v === null || v === undefined ? x(d) : v;
}
function transition(g) {
return g.transition().duration(500);
}
// Returns the path for a given data point.
function path(d) {
return line(dimensions.map(function(p) {
return [position(p), y[p](d[p])];
}));
}
function brushstart() {
d3.event.sourceEvent.stopPropagation();
}
function within(d, extent){
return extent[1] <= d && d <= extent[0];
}
// Handles a brush event, toggling the display of foreground lines.
function brush_parallel_chart() {
for(var i = 0; i < dimensions.length; ++i){
if(d3.event.target === y[dimensions[i]].brush) {
extents[i] = d3.event.selection.map(y[dimensions[i]].invert,y[dimensions[i]]);
}
}
foreground.style("display", function(d) {
return dimensions.every(function(p, i) {
if(extents[i][0]===0 && extents[i][1]===0) {
return true;
}
return within(d[p], extents[i])
}) ? null : "none";
});
selected = data.filter(function(item){
if(dimensions.every(function(dim, index){
if(extents[index][0]===0 && extents[index][1]===0) {
return true;
}
return within(item[dim], extents[index]);
})){
return true;
}
});
scope.onBrush({item: selected});
}
答案 0 :(得分:1)
乐队规模是此数据的错误工具。
问题是频段规模具有相关的带宽。因此,当您使用波段比例时,它将返回相应带宽的左边距(或者换句话说,&#34;步骤&#34;的左边距):
使用5个值以及从0
到100
的范围来查看带范围返回的值:
var data = "abcde".split("")
var s = d3.scaleBand()
.domain(data)
.range([0, 100]);
data.forEach(function(d) {
console.log(s(d))
})
&#13;
<script src="https://d3js.org/d3.v4.min.js"></script>
&#13;
如果将填充设置为1,将有助于减少带宽,但不会那么多(以下更多内容):
var data = "abcde".split("")
var s = d3.scaleBand()
.domain(data)
.range([0, 100])
.padding(1);
data.forEach(function(d) {
console.log(s(d))
})
&#13;
<script src="https://d3js.org/d3.v4.min.js"></script>
&#13;
<强>解决方案强>:
使用点刻度。点比例没有带宽:
以下是演示,请查看值:
var data = "abcde".split("")
var s = d3.scalePoint()
.domain(data)
.range([0, 100]);
data.forEach(function(d) {
console.log(s(d))
})
&#13;
<script src="https://d3js.org/d3.v4.min.js"></script>
&#13;
关于填充,因为我说&#34;更多关于下面&#34; :你几乎把它弄好了!问题是padding
是......
...一种方便的方法,用于将内部和外部填充设置为相同的填充值。
因此,它设置内部和外部填充。如果您使用paddingInner(1)
和paddingOuter(0)
,您将得到相同的点数结果:
var data = "abcde".split("")
var s = d3.scaleBand()
.domain(data)
.range([0, 100])
.paddingInner(1)
.paddingOuter(0);
data.forEach(function(d) {
console.log(s(d))
})
&#13;
<script src="https://d3js.org/d3.v4.min.js"></script>
&#13;
答案 1 :(得分:-2)
尝试将margin
更改为:
var margin = {top: 20, right: 0, bottom: 10, left: 0},
在第一行。边距是图表周围的空间。这也应该改变width
的值,它使用声明中的边距。由于宽度将增加,x比例应该改变,使“尺寸”等间隔但彼此进一步分开。