Question

我试图将一个字符串放在get的json数组中，但JArray.Parse失败，因为该字符串首先不是一个有效的json对象。如何将逗号分隔的字符串转换为json？

输入就像

34520,63631,45628

代码如下;

public static string GetLocationInZips(string strZipCodes)
        {
            JArray jarrZipCodes = new JArray();
            JObject response = new JObject();

            try
            {
                jarrZipCodes = JArray.Parse(strZipCodes);
            }
            catch(Exception ex)
            {
                response["success"] = false;
                response["error"] = "Failed to serialize zip code array, please check and try again";
                response["exception"] = ex.ToString();

                return response.ToString();
            }
        }

Answer 1

不要使用JArray。使用JsonConvert.SerializeObject(strZipCodes.Split(','))，因为您需要来自字符串数组的JSON数组。如果您无法使用JsonConvert中的NewtonSoft.JSON，请使用JavascriptSerializer。

  //Call below function like 

 var jsonZipCodes = GetLocationInZips("34520,63631,45628");

  public static string GetLocationInZips(string strZipCodes)
    {
        string jarrZipCodes = string.Empty;
        JObject response = new JObject();

        try
        {

     //       jarrZipCodes = JsonConvert.SerializeObject(strZipCodes.Split(','));
           jarrZipCodes = new System.Web.Script.Serialization.JavaScriptSerializer().Serialize(strZipCodes.Split(','));
            return jarrZipCodes;
        }
        catch (Exception ex)
        {
            response["success"] = false;
            response["error"] = "Failed to serialize zip code array, please check and try again";
            response["exception"] = ex.ToString();

            return response.ToString();
        }
    }

Answer 2

使用Json.net库进行此操作。您可以使用Split()函数将值拆分为数组，以分别处理每个值。

然后使用JsonConvert.SerializeObject转换为JSON。

请参阅Convert comma seperated string to json了解一个很好的例子

Answer 3

您可以拆分字符串以获取数组并使用JArray.FromObject，如下所示：

string testInput = "34520,63631,45628";
JArray array = JArray.FromObject(testInput.Split(','));

Answer 4

感谢下面的Amit是最终的解决方案。

public static string GetLocationInZips(string strZipCodes)
        {
            JArray jarrZipCodes = new JArray();
            string jarrZipCode = string.Empty;
            JObject response = new JObject();

            jarrZipCode = JsonConvert.SerializeObject(strZipCodes.Split(','));

            try
            {
                jarrZipCodes = JArray.Parse(jarrZipCode);
            }
            catch(Exception ex)
            {
                response["success"] = false;
                response["error"] = "Failed to serialize zip code array, please check and try again";
                response["exception"] = ex.ToString();

                return response.ToString();
            }

将get方法中的字符串转换为有效的json c＃

4 个答案: