Question

当EditText为空且按下按钮时，android应用程序崩溃如果一个或多个edittext为空并按下该按钮会导致错误。

这是代码：

public class Tab4Weight extends  Fragment {
       EditText firstNumber;
       EditText secondNumber;
       TextView addResult;
       Button btnAdd;

       @Override
      public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
          View view = inflater.inflate(R.layout.tab4weight, container, false);

          firstNumber = (EditText)view.findViewById(R.id.txtNumber1);
          secondNumber = (EditText)view.findViewById(R.id.txtNumber2);
          addResult = (TextView)view.findViewById(R.id.txtResult);
          btnAdd = (Button)view.findViewById(R.id.btnAdd);
          btnAdd.setOnClickListener(new View.OnClickListener() {

          @Override
          public void onClick(View v) {
             String value1= firstNumber.getText().toString();
             String value2= secondNumber.getText().toString();
             int a=Integer.parseInt((value1));
             int b=Integer.parseInt((value2));

             int sum= getCoordinates(a,b);
             Toast.makeText(getActivity(),"Weight in Kg: " + 
             String.valueOf(sum),Toast.LENGTH_LONG).show();

          }

          private int getCoordinates (int coordA, int coordB){
              int results = 0;
              if (coordA < 7000 && coordB < 30 && coordB > -45)
              {
                  results = 7400;
              }

              else{
                  if (coordA==8000 && coordB ==30)
                  {
                      results = 7100;
                  }


       firstNumber.addTextChangedListener(new TextWatcher() {
          @Override
          public void beforeTextChanged(CharSequence s, int start, int count, int after) {

              }

          @Override
          public void onTextChanged(CharSequence s, int start, int before, int count) {

          }

          @Override
          public void afterTextChanged(Editable s) {int jumlah = Integer.parseInt(firstNumber.getText().toString());

          if( firstNumber.getText().toString().equals("")||jumlah > 10001 
           && jumlah < 10999) {
                firstNumber.setText("11000");
                return;
            }
            else {
                if (firstNumber.getText().toString().equals("") || jumlah > 
            11001 && jumlah < 11999) {
                    firstNumber.setText("12000");
                }
                else {
                    if (firstNumber.getText().toString().equals("") || 
             jumlah > 12001 && jumlah < 12999) {
                        firstNumber.setText("13000");
                    }

当edittext为空并按下按钮时，android应用程序崩溃如果一个或多个edittext为空

你能帮帮我吗

Answer 1

试试这个，你需要首先检查你的Edittext值是否为空

使用 isEmpty(CharSequence str) 检查您的Edittext是否为空

如果字符串为null或0-length，则返回true。

btnAdd.setOnClickListener(new View.OnClickListener() {
          @Override
          public void onClick(View view) {
              if(!TextUtils.isEmpty(firstNumber.getText().toString())&&!TextUtils.isEmpty(secondNumber.getText().toString())){
                  String value1= firstNumber.getText().toString();
                  String value2= secondNumber.getText().toString();
                  int a=Integer.parseInt((value1));
                  int b=Integer.parseInt((value2));

                  int sum= getCoordinates(a,b);
                  Toast.makeText(getActivity(),"Weight in Kg: " +
                          String.valueOf(sum),Toast.LENGTH_LONG).show();
              }else {
                  Toast.makeText(getActivity(), "value is empty", Toast.LENGTH_SHORT).show();
              }

          }
      });

当edittext为空并按下按钮时，android应用程序崩溃

1 个答案: