Question

我想从xsd生成xml，这个xml我想要包含来自xsd的指定属性。有什么想法吗？

string fn = System.IO.Path.GetFileName(File1.PostedFile.FileName);
    string SaveLocation = Server.MapPath("Data") + "\\" + fn;
    try
    {
        File1.PostedFile.SaveAs(SaveLocation);
        Response.Write("The file has been uploaded.");
    }
    catch (Exception ex)
    {
        Response.Write("Error: " + ex.Message);
        //Note: Exception.Message returns a detailed message that describes the current exception. 
        //For security reasons, we do not recommend that you return Exception.Message to end users in 
        //production environments. It would be better to put a generic error message. 
    }
    try
    {
        XmlTextReader reader = new XmlTextReader(SaveLocation);
        //XmlSchema myschema = XmlSchema.Read(reader, ValidationCallback);
        while (reader.Read())
        {
           // LiteralURL.Text += reader.ReadString();
        }
        // Response.Write("\t"+myschema.Items);
        XDocument doc = XDocument.Load(SaveLocation);
        var ListNode = new List<XNode>();
        if (doc != null)
        {
            Response.Write("nu este null");
        }
        else
        {
            Response.Write("Null !");
        }
        int i = 0;
       string str = "";
        foreach (XNode nodes in doc.Elements())
        {

            str = "node1:  " + nodes.ToString();
            ListNode[i] = nodes;
            i++;

        }

       for(int j = 0; j < i; i++)
        {
            Response.Write("FirstNode:"+ ListNode[j]);

        }
        //Response.Write("FirstNode:" );
        Response.Write(str);
    }
    catch (Exception ex)
    {
    }

}
else
{
    Response.Write("Please select a file to upload.");
}

Answer 1

看看xsd.exe。您针对XSD运行此操作，它会根据XSD元素和属性为您提供类。在此之后，您不需要使用原始XML或XSD。

使用ado.net从Xsd生成Xml

1 个答案: