Question

我需要能够找到5个连续的EEPROM存储器位，理想情况下最接近2（因为我有与其他数据相关的位＃1和2，并希望保持组织有序）。我开发了这个有效的代码，但for循环在找到一组好的数字后继续。

Serial.println("got to assignment number finder");
for (int AssignCheck = 2; AssignCheck < 250; AssignCheck++){
  Serial.println("Finding a good assignment number " + String(AssignCheck));
  if (EEPROM.read(AssignCheck) == 255){          //Looks for a blank space which can be used to store the new card
    if (EEPROM.read(AssignCheck + 1) == 255){
      if (EEPROM.read(AssignCheck + 2) == 255){
        if (EEPROM.read(AssignCheck + 3) == 255){
          if (EEPROM.read(AssignCheck + 4) == 255){
            Serial.println("Found assignment numbers " + String(AssignCheck) + " through to " + String(int(AssignCheck) + 4) + ".  Scanner value = " + String(Scanner));
            int StoreValue = AssignCheck;
          }
        }
      }
    }
  }
}

然后我想我可以在它周围放一个while循环，并且一旦变量设置为0而不是1就让while循环停止，所以我写了这个:(注意while循环的引入，变量和中间的Scanner = 0行。

Serial.println("got to assignment number finder");
int Scanner = 1;
while (Scanner == 1){
  for (int AssignCheck = 2; AssignCheck < 250; AssignCheck++){
    Serial.println("Finding a good assignment number " + String(AssignCheck) + ".  Scanner value = " + String(Scanner));
    if (EEPROM.read(AssignCheck) == 255){          //Looks for a blank space which can be used to store the new card
      if (EEPROM.read(AssignCheck + 1) == 255){
        if (EEPROM.read(AssignCheck + 2) == 255){
          if (EEPROM.read(AssignCheck + 3) == 255){
            if (EEPROM.read(AssignCheck + 4) == 255){
              Scanner = 0;
              Serial.println("Found assignment numbers " + String(AssignCheck) + " through to " + String(int(AssignCheck) + 4) + ".  Scanner value = " + String(Scanner));
              int StoreValue = AssignCheck;
            }
          }
        }
      }
    }
  }
}

它在我想要时正确识别并将变量设置为0，但是while循环似乎没有影响，循环继续产生可以工作的数字集。

作为一名新手编码员，我不确定接下来会尝试什么。

非常感谢任何建议。

Answer 1

在这种情况下，您可以使用说明break：

Serial.println("got to assignment number finder");
for (int AssignCheck = 2; AssignCheck < 250; AssignCheck++){
  Serial.println("Finding a good assignment number " + String(AssignCheck));
  if (EEPROM.read(AssignCheck) == 255){          //Looks for a blank space which can be used to store the new card
    if (EEPROM.read(AssignCheck + 1) == 255){
      if (EEPROM.read(AssignCheck + 2) == 255){
        if (EEPROM.read(AssignCheck + 3) == 255){
          if (EEPROM.read(AssignCheck + 4) == 255){
            Serial.println("Found assignment numbers " + String(AssignCheck) + " through to " + String(int(AssignCheck) + 4) + ".  Scanner value = " + String(Scanner));
            int StoreValue = AssignCheck;
            break;
          }
        }
      }
    }
  }
}

正如您可以阅读here，它完全符合您的要求。

请注意，您的第二次尝试不起作用，因为for loop在一段时间内：它在整个for loop之前完成，之后，它会比较“扫描仪“while loop

的变量

你可以这样纠正：

Serial.println("got to assignment number finder");
int Scanner = 1;
for (int AssignCheck = 2; (AssignCheck < 250) && (Scanner == 1); AssignCheck++){
  Serial.println("Finding a good assignment number " + String(AssignCheck) + ".  Scanner value = " + String(Scanner));
  if (EEPROM.read(AssignCheck) == 255){          //Looks for a blank space which can be used to store the new card
    if (EEPROM.read(AssignCheck + 1) == 255){
      if (EEPROM.read(AssignCheck + 2) == 255){
        if (EEPROM.read(AssignCheck + 3) == 255){
          if (EEPROM.read(AssignCheck + 4) == 255){
            Scanner = 0;
            Serial.println("Found assignment numbers " + String(AssignCheck) + " through to " + String(int(AssignCheck) + 4) + ".  Scanner value = " + String(Scanner));
            int StoreValue = AssignCheck;
          }
        }
      }
    }
  }
}

Answer 2

读取EEPROM很贵，请考虑一下：

Serial.println("got to assignment number finder");
int Scanner = 1;
char rollingBuffer[5];
rollingBuffer[0] = EEPROM.read(2 + 0);
rollingBuffer[1] = EEPROM.read(2 + 1);
rollingBuffer[2] = EEPROM.read(2 + 2);
rollingBuffer[3] = EEPROM.read(2 + 3);
rollingBuffer[4] = EEPROM.read(2 + 4);
pointRoll = 0;
for (int AssignCheck = 7; (AssignCheck < 255); AssignCheck++)
{
    if ((rollingBuffer[0] == 255) && (rollingBuffer[1] == 255) && (rollingBuffer[2] == 255) && (rollingBuffer[3] == 255) && (rollingBuffer[4] == 255))
    {
        Serial.println("Found assignment numbers " + String(AssignCheck-5) + " through to " + String(int(AssignCheck-1)) + ".  Scanner value = " + String(Scanner));
        int StoreValue = AssignCheck;
        break;
    }
    rollingBuffer[pointRoll] = EEPROM.read(AssignCheck);
    pointRoll++;
    if (pointRoll > 4) pointRoll = 0;
}

继续循环，直到完成目标

2 个答案: