Question

我正在尝试根据用户输入的行数和列数创建按钮网格，并且创建网格的方法不起作用。当我调用它时，网格不会被创建。

该方法在我的TileClass中，我试图以我的GameBoard形式调用它。我觉得我没有正确使用这门课程。我认为我没有正确地调用该方法，因为我认为这应该有效。

  class TileClass : Button
{
    public const int LEFT = 20;
    public const int WIDTH = 50;
    public const int HEIGHT = 50;
    public const int TOP = 50;
    public const int VGAP = 30;
    public int x;
    public int y;
    public int column;
    public int row;
    private int incomingRow;
    private int incomingColumn;

    public int IncomingRow { get => incomingRow; set => incomingRow = value; }
    public int IncomingColumn { get => incomingColumn; set => incomingColumn = value; }

    public TileClass()
    {

    }
    public void CreateGrid()
    {
        x = LEFT;
        y = TOP;
        column = IncomingColumn;
        row = IncomingRow;

        for (int i = 0; i < row; i++)
        {
            for (int j = 0; j < column; j++)
            {
                Button b = new Button();
                b.Left = x;
                b.Top = y;
                b.Width = WIDTH;
                b.Height = HEIGHT;
                b.Text = j.ToString();

                x += VGAP + HEIGHT;
                this.Controls.Add(b); 
            }
        }
    }
}

游戏板表格

 public partial class GameBoard : Form
{
    TileClass tileClass = new TileClass();

    public GameBoard()
    {
        InitializeComponent();
    }

    private void txtEnter_Click(object sender, EventArgs e)
    {

        tileClass.IncomingColumn = int.Parse(txtColumn.Text);
        tileClass.IncomingRow = int.Parse(txtRow.Text);
        tileClass.CreateGrid();

    }

Answer 1

要实现这一目标还有很多工作要做：

class TileClass : Panel
{
...
    public int IncomingRow {get; set;}
    public int IncomingColumn { get; set; }
...
}

并删除：

private int incomingRow;
private int incomingColumn;

并且理想的方法是在添加按钮之前使用ResumeLayout，并通过调用Invalidate让Gameboard表单重绘。 What does invalidate method do? 注意：尝试col = 100，row = 100，有和没有ResumeLayout＆amp; Invalidate

public partial class GameBoard : Form
{
    public GameBoard ()
    {
        InitializeComponent();

        tileClass.Dock = DockStyle.Fill;
        this.Controls.Add(tileClass);
    }

    TileClass tileClass = new TileClass();

    private void txtEnter_Click(object sender, EventArgs e)
    {

        tileClass.IncomingColumn = int.Parse(txtColumn.Text);
        tileClass.IncomingRow = int.Parse(txtRow.Text);

        this.ResumeLayout(); //Important
        tileClass.CreateGrid();
        this.Invalidate(); // Important
    }
}

你可以设置更多属性，它需要的不仅仅是：

//tileClass.Location = new Point(10, 10); // not sure
tileClass.Dock = DockStyle.Fill;
//tileClass.Size = new Size(200, 200); // not sure

而不是j＆lt; 5你应该使用col和row：

for (int i = 0; i < row; i++)
{
    for (int j = 0; j < column; j++)
    {
        Button b = new Button();
        b.Left = x;
        b.Top = y;
        b.Width = WIDTH;
        b.Height = HEIGHT;
        b.Text = string.Format("({0},{1})" , i, j);

        x += VGAP + HEIGHT;
        this.Controls.Add(b);
    }
    x = LEFT; // not sure, plz calculate!
    y += Top * (i+1); // not sure, plz calculate!
}

如何通过类中创建的方法在表单上创建按钮？

1 个答案: