如何在以下代码中旋转x-tick标签?
我想使用fig.autofmt_xdate()
,因为x-tick标签是日期,但我不知道如何以及在何处实现它。除此之外,代码似乎对我到目前为止发现的旋转命令“免疫”
代码与此一般example中的代码几乎相同。
import matplotlib
from mpl_toolkits.axes_grid1 import host_subplot
import mpl_toolkits.axisartist as AA
import matplotlib.pyplot as plt
import numpy as np
import locale
locale.setlocale(locale.LC_ALL, 'German')
CSB = [9205.0, 8845.0, 19740.0, 410.0, 11560.0, 11632.0, 14368.0,
11556.0, 9846.0, 14544.0]
DOC = [np.nan, 1853.0, 4172.0, 259.0, np.nan, np.nan, np.nan, np.nan,
np.nan, np.nan]
NH3N = [3593.5, 3318.8, 5208.0, 306.4, 2708.2, 2682.1, 2812.3, 3033.1,
3098.4, 3815.9]
x = np.linspace(1, 10, 10)
Daten = ['09.05.2017', '16.05.2017', '23.05.2017', '06.06.2017', '28.08.2017',
'31.08.2017', '04.09.2017', '07.09.2017', '14.09.2017', '18.09.2017']
font = {'family' : 'Arial',
'size' : 12}
matplotlib.rc('font', **font)
host = host_subplot(111, axes_class=AA.Axes)
plt.subplots_adjust(right=0.75)
par1 = host.twinx()
par2 = host.twinx()
host.get_yaxis().set_major_formatter(plt.FuncFormatter(lambda x,
loc: "{0:n}".format(float(x))))
par1.get_yaxis().set_major_formatter(plt.FuncFormatter(lambda x,
loc: "{0:n}".format(float(x))))
par2.get_yaxis().set_major_formatter(plt.FuncFormatter(lambda x,
loc: "{0:n}".format(float(x))))
offset = 85
new_fixed_axis = par2.get_grid_helper().new_fixed_axis
par2.axis["right"] = new_fixed_axis(loc="right",
axes=par2,
offset=(offset, 0))
par2.axis["right"].toggle(all=True)
host.set_xlim(0, 11)
host.set_ylim(0, 10000)
host.set_xlabel("Datum Probenahme")
host.set_ylabel(r'NH$_3$-N-Konzentration $[\frac{mg}{L}]$')
par1.set_ylabel(r'CSB-Konzentration $[\frac{mg}{L}]$')
par2.set_ylabel(r'DOC-Konzentration $[\frac{mg}{L}]$')
host.set_xticks(x)
host.set_xticklabels(Daten)
p1, = host.plot(x, NH3N, '+k', label='NH$_3$-N-Konzentration')
p2, = par1.plot(x, CSB, '.k', label=r'CSB-Konzentration')
p3, = par2.plot(x, DOC, '^k', label=r'DOC-Konzentration')
par1.set_ylim(0, 25000)
par2.set_ylim(0, 5000)
host.legend(loc=9, ncol = 3, bbox_to_anchor=(0.75, -0.2))
plt.draw()
plt.show()
这个数字现在看起来像this。
答案 0 :(得分:0)
我不是这个HostAxes
演示的忠实粉丝。除了axes_grid
工具包是各种错误的来源之外,它甚至都不容易理解。
我一般建议使用正常的子图。在this answer by @smoneck中有一个很好的复制官方示例。
因此,使用正常的子图和轴,您可以得到类似的内容,只需使用fig.autofmt_xdate()
即可。
import matplotlib.pyplot as plt
import numpy as np
CSB = [9205.0, 8845.0, 19740.0, 410.0, 11560.0, 11632.0, 14368.0,
11556.0, 9846.0, 14544.0]
DOC = [np.nan, 1853.0, 4172.0, 259.0, np.nan, np.nan, np.nan, np.nan,
np.nan, np.nan]
NH3N = [3593.5, 3318.8, 5208.0, 306.4, 2708.2, 2682.1, 2812.3, 3033.1,
3098.4, 3815.9]
x = np.linspace(1, 10, 10)
Daten = ['09.05.2017', '16.05.2017', '23.05.2017', '06.06.2017', '28.08.2017',
'31.08.2017', '04.09.2017', '07.09.2017', '14.09.2017', '18.09.2017']
font = {'family' : 'Arial',
'size' : 12}
plt.rc('font', **font)
fig = plt.figure()
host = fig.add_subplot(111)
par1 = host.twinx()
par2 = host.twinx()
host.get_yaxis().set_major_formatter(plt.FuncFormatter(lambda x,
loc: "{0:n}".format(float(x))))
par1.get_yaxis().set_major_formatter(plt.FuncFormatter(lambda x,
loc: "{0:n}".format(float(x))))
par2.get_yaxis().set_major_formatter(plt.FuncFormatter(lambda x,
loc: "{0:n}".format(float(x))))
offset = 85
par2.spines['right'].set_position(('outward', offset))
host.set_xlim(0, 11)
host.set_ylim(0, 10000)
host.set_xlabel("Datum Probenahme")
host.set_ylabel(r'NH$_3$-N-Konzentration $[\frac{mg}{L}]$')
par1.set_ylabel(r'CSB-Konzentration $[\frac{mg}{L}]$')
par2.set_ylabel(r'DOC-Konzentration $[\frac{mg}{L}]$')
host.set_xticks(x)
host.set_xticklabels(Daten)
p1, = host.plot(x, NH3N, '+k', label='NH$_3$-N-Konzentration')
p2, = par1.plot(x, CSB, '.k', label=r'CSB-Konzentration')
p3, = par2.plot(x, DOC, '^k', label=r'DOC-Konzentration')
par1.set_ylim(0, 25000)
par2.set_ylim(0, 5000)
#host.legend(loc=9, ncol = 3, bbox_to_anchor=(0.75, -0.2))
fig.autofmt_xdate()
plt.tight_layout()
plt.show()