Question

我有这个JSON：

modelBuilder.Entity<Author>()
    .HasOne(e => e.Address)
    .WithOne()
    .HasForeignKey<Address>("AuthorId")
    .OnDelete(DeleteBehavior.Cascade);

modelBuilder.Entity<Publisher>()
    .HasOne(e => e.Address)
    .WithOne()
    .HasForeignKey<Address>("PublisherId")
    .OnDelete(DeleteBehavior.Cascade);

属性的名称将是动态的，也是JSON的长度。我正在使用GSON工具，我创建了一个POJO，但没有名称，我无法引用它，这就是为什么我收到myError实例，为null。这是我的POJO

{
    "username": [
        "A user with that username already exists."
    ],
    "ruc": [
        "user with this ruc already exists."
    ],
    "code": [
        "user with this code already exists."
    ],
    "document_number": [
        "user with this document number already exists."
    ]
}

这是我的GSON代码

public class MyError {
    public Map<String, Object> message = new HashMap<>();
}

我想为每个项目显示一条消息：

myError = new Gson().fromJson(response.errorBody().string(), MyError.class);

Answer 1

你可以尝试使用它：

Map myError = new Gson().fromJson(s, Map.class);

或者如果你想使用你的类，json应该如下：

{ "message": { "username": [ "A user with that username already exists." ], "ruc": [ "user with this ruc already exists." ], "code": [ "user with this code already exists." ], "document_number": [ "user with this document number already exists." ] } }

Answer 2

几个月前我有一个类似的问题，发现这个答案非常有帮助：

How to parse dynamic JSON fields with GSON?

Answer 3

考虑使用Gson和java原生JsonParser。

如何在没有名称和动态的情况下反序列化json对象？

3 个答案: