Question

用户输入字符串值并存储。该字符串中的每个字符都放在一个数组中。数组的每个元素都被修改; （找到字符的ascii值，然后进行计算以更改ascii值）。通过替换先前修改过的元素，将新修改的数字添加到数组中。代码可以在这里显示：

NSString *toEncryptMessage = _message.text;
    NSMutableArray *characters = [[NSMutableArray alloc]initWithCapacity:[toEncryptMessage length]];
    int encrypted_power;
    int encrypted_number;
    for (int i = 0; i <[toEncryptMessage length]; i++){

        NSString* subchar = [toEncryptMessage 
substringWithRange:NSMakeRange(i, 1)];
        if (subchar) [characters addObject:subchar];
        unichar chr = [subchar characterAtIndex:0];
        encrypted_power = pow(chr,e);
        encrypted_number = encrypted_power % N;
        NSLog(@"ascii value %d", chr);

        [characters replaceObjectAtIndex:i withObject:[NSNumber 
    numberWithInt: encrypted_number]];

    }
    NSLog(@"%@", characters);
}

然而，我遇到的问题是＆＃39; encrypted_power＆＃39;是一个负数。 Encrypted_power是“e”的幂的ascii值，其中e = 7（之前在其他地方计算过）。

我在＆＃39; pow＆＃39;中添加了一个断点。线和插入＆＃39; hi＆＃39;待修改：

e = 7
toEncryptMessage = (NSTaggedPointerString *)    @"hi" 0xa000000000069682
characters  __NSArrayM *    @"1 element"    0x00006080002513d0
encrypted_power = (int) -2147483648
encrypted_number = (int) -2
i = 0

然后尝试修改下一个字符：

encrypted_power = (int) -2147483648
encrypted_number = (int) -2
i = (int) 1
subchar = (NSTaggedPointerString) @"i"
chr unichar U+0068 u'i'

在日志中是这样的：

Prototype2[56766:1730834] (
"-2",
"-2"
)
2017-10-12 16:54:21.766561 Prototype2[56766:1730834] [Common] 
_BSMachError: port 7417; (os/kern) invalid capability (0x14) "Unable to 
insert COPY_SEND"
2017-10-12 16:54:21.767494 Prototype2[56766:1730834] [Common] 
_BSMachError: port 7417; (os/kern) invalid name (0xf) "Unable to 
deallocate send right"

任何帮助都很好，谢谢。

如何修改NSString中的每个字符然后将其放入数组？

0 个答案: