Question

我是Android的新手，我正在开发一个应用程序，从bitrex获取当前速率并将其转换为印度卢比，但问题是我想在每一秒刷新速率，但我的处理程序只运行一次并且没有更改即使费率在bitrex API中发生变化，它在第一次之后的值

这是我的活动

public class Test extends AppCompatActivity {
double last;
double inr;
double x;


TextView tv, tt, ui,uer;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_test);





    uer=(TextView)findViewById(R.id.usern);
    ui = (TextView) findViewById(R.id.uid);
    tv = (TextView) findViewById(R.id.name);
    tt = (TextView) findViewById(R.id.email);


    final RequestQueue queue = Volley.newRequestQueue(this);
    final RequestQueue queuee = Volley.newRequestQueue(this);

    String url = "https://bittrex.com/api/v1.1/public/getticker?market=usdt-btc";
    String urll="http://api.fixer.io/latest?base=USD";

    final StringRequest stringRequest = new StringRequest(Request.Method.GET, url,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {

                    JSONObject json = null;
                    try {
                        json = new JSONObject(response);
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                    try {
                        JSONObject result = json.getJSONObject("result");

                        last = result.getDouble("Last");
                        tv.setText(String.valueOf(last));
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }
            }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {

        }
    });


    final StringRequest stringRequestmoney = new StringRequest(Request.Method.GET, urll,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {


                    JSONObject jjson = null;
                    try {
                        jjson = new JSONObject(response);
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                    try {
                        JSONObject money = jjson.getJSONObject("rates");
                        inr = money.getDouble("INR");
                        tt.setText(String.valueOf(inr));
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }
            }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {

        }
    });


//        queue.add(stringRequest);
//        queuee.add(stringRequestmoney);
    final Handler handler = new Handler();

    handler.postDelayed(new Runnable() {
                            public void run() {
                                //do something
                                queue.add(stringRequest);
                                queuee.add(stringRequestmoney);
                                x = (last * inr);     
                                ui.setText(""+x);
                                handler.postDelayed(this, 5000);

                            }
                        }, 5000);



}

Answer 1

我不知道如果这是你的问题的根源，但试图抓住你的处理程序中的任何错误

 handler.postDelayed(new Runnable() {
                     public void run() {
                                try{
                                    //do something
                                    queue.add(stringRequest);
                                    queuee.add(stringRequestmoney);
                                    x = (last * inr);     
                                    ui.setText(""+x);
                                    handler.postDelayed(this, 5000);
                          }
                       finally {
                       // 100% guarantee that this always happens, even if
                       // your update method throws an exception
                        handler.postDelayed(this, 5000);
                                 }
                                }
                            }, 5000);

为什么我的处理程序只运行一次刷新数据

1 个答案: