Question

我试过的PCRE Regex找到了第一个字符并删除了其后的所有内容。

以下是字符串示例：

$128.48 One Month TV Internet and Voice, 100GB of Fiber<sup>&dagger;</sup> Internet.

$148.48 One Month TV Internet and Voice, 200GB of Fiber<sup>&dagger;</sup> Internet and a free movie rental from MoviePlex.

我想从String中提取以下字符，并保持String的其余部分不变。摘录：<sup>&dagger </sup>

预期结果：

$148.48 One Month TV Internet and Voice, 200GB of Fiber;Internet and a free movie rental from MoviePlex.

$128.48 One Month TV Internet and Voice, 100GB of Fiber; Internet.

这是我试过的正则表达式：

[^&dagger<sup><\/sup>]*

Answer 1

That's how you could do this in Perl：

#!/usr/bin/perl
use strict;
use warnings FATAL => 'all';

use Data::Dumper;

my @strings = (
    '$128.48 One Month TV Internet and Voice, 100GB of Fiber<sup>&dagger;</sup> Internet.',
    '$148.48 One Month TV Internet and Voice, 200GB of Fiber<sup>&dagger;</sup> Internet and a free movie rental from MoviePlex.'
);

my @updated_strings = map { my $str = $_; $str =~ s/<sup>.+?<\/sup>/;/; $str; } @strings;

print 'UPDATED: ' . Dumper(\@updated_strings) . "\n";

你也可以在语言无关的regex101.com中使用它：example

正则表达式PCRE - 仅删除字符串

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