Question

我正在尝试使用表单上的选择框的name属性来使用更新查询。一切都传递到$ _POST并且INSERT查询工作正常，但我无法弄清楚为什么我的if语句的更新部分没有进入我的数据库。任何建议都非常感谢。

<?php

global $wpdb;

$Call_Number = $_POST['Call_Number'];
$datas = $_POST['REG'];
$columns = implode(",",array_keys($datas));
$values = implode("','",$datas);

$result = $wpdb->get_results ("SELECT Call_Number FROM DG_Pro_Coach WHERE Call_Number = '".$Call_Number."'");

if (count ($result) > 0) {
    $row = current ($result);
    $wpdb->query ("UPDATE DG_Pro_Coach SET ".$columns."='".$values."' WHERE Call_Number = '".$Call_Number."'");
} else {
    $wpdb->query("INSERT INTO DG_Pro_Coach (".$columns.",Call_Number ) VALUES ('".$values."','$Call_Number' )");
}

?>

Answer 1

<强>问题

您的查询应如下所示：

UPDATE database SET column1=value1, column2=value2(...) WHERE condition

但它看起来像这样：

UPDATE database SET column1,column2(...) = value1,value2(...) WHERE condition

<强>解决方案

<?php

global $wpdb;

$Call_Number = $_POST['Call_Number'];
$datas = $_POST['REG'];
$columns = implode(",",array_keys($datas));
$values = implode("','",$datas);
$updatelist = "";
foreach($datas as $key=>$value){
    $updatelist .= $key."=".$value.",";
}
$updatelist = substr($updatelist,0,strlen($updatelist)-1);

$result = $wpdb->get_results ("SELECT Call_Number FROM DG_Pro_Coach WHERE Call_Number = '".$Call_Number."'");

if (count ($result) > 0) {
    $row = current ($result);
    $wpdb->query ("UPDATE DG_Pro_Coach SET ".$updatelist."' WHERE Call_Number = '".$Call_Number."'");
} else {
    $wpdb->query("INSERT INTO DG_Pro_Coach (".$columns.",Call_Number ) VALUES ('".$values."','$Call_Number' )");
}

?>

Answer 2

您的更新查询语法错误，因为您以错误的方式包含PHP数组中的数据。

对于那些输入参数：

$Call_Number = '123456789';
$datas = array('one' => 1, 'two' => 2);

创建此查询：

UPDATE DG_Pro_Coach SET one,two='1','2' WHERE Call_Number = '123456789'

可能的解决方案：

$update_array = array();
foreach ($datas as $column=>$value) {
  $update_array[] = "$column = '$value'";
}
$update_string = implode(', ', $update_array);

$wpdb->query ("UPDATE DG_Pro_Coach SET ".$update_string.' WHERE Call_Number = '".$Call_Number."'");

Answer 3

非常感谢所有的帮助，这是工作代码。

<?php

global $wpdb;

$Call_Number = $_POST['Call_Number'];
$datas = $_POST['REG'];
$columns = implode(",",array_keys($datas));
$values = implode("','",$datas);
$updatelist = "";
foreach($datas as $key=>$value){
$updatelist .= $key."='".$value."', ";
}
$updatelist = substr($updatelist,0,strlen($updatelist)-2);

$result = $wpdb->get_results ("SELECT Call_Number FROM DG_Pro_Coach WHERE Call_Number = '".$Call_Number."'");

if (count ($result) > 0) {
$row = current ($result);
$wpdb->query ("UPDATE DG_Pro_Coach SET ".$updatelist." WHERE Call_Number = '".$Call_Number."'");
} else {
$wpdb->query("INSERT INTO DG_Pro_Coach (".$columns.",Call_Number ) VALUES ('".$values."','$Call_Number' )");
}

?>

使用“选择名称”属性更新查询

3 个答案: