flexjson.JSONException不知道如何绑定

时间:2017-10-12 09:00:40

标签: java android json flexjson

我的android应用程序使用flexjson库来反序列化通过RESTfull webservice从服务器接收的json数据字符串。但是当反序列化时我会得到错误。

  

flexjson.JSONException:[data.status]:不知道如何将Clock_in绑定到类wfa.com.tma.wfa.type.TimeClockStatus中。您可能需要使用ObjectFactory而不是普通类。

这是我的字符串

{
  "data":
     {
       "todayShift":
           {
              "startTime":"1970-01-01T13:30:00Z",
              "endTime":"1970-01-02T00:00:00Z",
              "office":
                    {
                       "id":1,"name":"Location Test 1"
                    }
          },
       "currentTime":"2017-10-12T07:47:11Z",
       "status":"Clock_in",
       "latestTime":"2017-10-12T07:46:13Z",
       "latestOffice":{"id":1,"name":"Location Test 1"}},
       "meta":{"type":"TimeClockDto"}
 }

此字符串的DTO

public class TimeClockDto implements Serializable
{
    private static final long serialVersionUID = 1L;
    private TodayShiftDto todayShift;
    private String currentTime;
    private TimeClockStatus status;
    private String latestTime;
    private BaseLocationDto latestOffice;
    public TimeClockDto(TodayShiftDto todayShift, String currentTime, 
    TimeClockStatus status, String latestClockInTime,
                        BaseLocationDto latestOffice)
    {
        this.todayShift = todayShift;
        this.currentTime = currentTime;
        this.status = status;
        this.latestTime = latestClockInTime;
        this.latestOffice = latestOffice;
    }
    //getter, setter
}

`和反序列化代码

和枚举类

public enum TimeClockStatus
{
Clock_in, Clock_out;
}

1 个答案:

答案 0 :(得分:0)

我使用EnumObjectFactory

解决了这个问题
TimeClockDto result = new JSONDeserializer<TimeClockDto>
                        .use("data", TimeClockDto.class)
                        .use("data.todayShift", TodayShiftDto.class)
                        .use("data.status", new EnumObjectFactory())
                        .use("data.latestOffice", BaseLocationDto.class)
                        .deserialize(param.getResult(),TimeClockDto.class);