如何在codeingiter中获取包含子字符串的所有文件，如“abc”

Question

我有很多文件名，例如“black_abc”，“white_abc”，“black_cde”，“white_abc”。如何只获取文件名包含“abc”的文件？

Answer 1

您可以使用strpos()吗？

http://php.net/manual/en/function.strpos.php

<?php
 $arr = ["black_abc","white_abc","black_cde","white_abc"];
 foreach($arr as $i => $item) {
   if (strpos($item, '_abc')) {
     echo 'found _abc in ' . $item;
     echo '<br>';
   }
 }
?>

输出：

found _abc in black_abc
found _abc in white_abc
found _abc in white_abc

Answer 2

使用glob()功能，如下所示：

<?php
$filename = "absolute path of the directory/*abc*";
foreach (glob($filename) as $filefound) {
    echo "$filefound size " . filesize($filefound) . "\n";
}
?>