Question

我很难知道如何从文本文件中获取POST数据。我的文本文件中包含以下文本：

2017年10月11日星期三，04：53 AM，reader_name =％22Impinj％20RFID％20Reader％22＆amp; mac_address =％2200％3a16％3a25％3a10％3a7E％3a85％22＆amp; line_ending =％0a＆amp; field_delim =％图2c＆安培; FIELD_NAMES =天线％5fport％2cepc％2cpeak％5frssi％2ctid＆安培; field_values = 1％2C％22503030393839343834323200％22％2C％2d50％2C％22E280110520005756DE620231％22％0A1％2C％22000000000000001000000441％22％2C％2d53％2C％ 22E28011602000728E91750917％22％0A1％2C％2288000008％22％2C％2D60％2C％22E280116020007224B7650909％22％0A1％2C％22000000000000001000000441％22％2C％2d54％2C％22E28011602000728E91750917％22％0A1％2C％22503030393839343834323200％22％2C％ 2d48％2C％22E280110520005756DE620231％22％0A

POST数据如下： reader_name，mac_address，line_ending，field_delim，field_names和field_values

我创建了一个代码，该代码将从文本文件中读取数据，但失败了：

<?php
$fn = "log.txt";
$read = readfile($fn);


// Store the POST variables.
$readerName = $_POST['reader_name'];
$macAddress = $_POST['mac_address'];
$lineEnding = $_POST['line_ending'];
$fieldDelim = $_POST['field_delim'];
$fieldNames = $_POST['field_names'];
$fieldValues = $_POST['field_values'];

//Connect to the database.
$con = mysqli_connect('localhost', 'root', '153624123', 'test') or die("Unable to select database");

// Replace the field delimiter with a comma.
str_replace($fieldDelim, ",", $fieldNames);

// Break the field values up into rows.
$rows = explode("\n", $fieldValues);

// Remove the last row. It's always blank
if (sizeof($rows))
    array_pop($rows);

$fieldNames = "reader_name,mac_address," . $fieldNames;

foreach ($rows as $row) {
    $row = $readerName . "," . $macAddress . "," .
            $row;
    $query = mysqli_query($con, "INSERT INTO tags ($fieldNames) VALUES ($row)");
    echo "INSERT INTO tags ($fieldNames) VALUES ($row)" . '<br />';
}
?>

我尝试在谷歌搜索其他方式，但没有找到运气。文本文件来自我们为我们的项目购买的RFID，称为＆＃34; speedway connect＆＃34;产品。它有一个网站，他们发布了HTTP POST的源代码。我跟着一切，但我没有运气。

https://support.impinj.com/hc/en-us/articles/202756148-HTTP-POST-with-Speedway-Connect-software-VIDEO-

Answer 1

使用以下内容：

$read = readfile($fn);
$string =urldecode(explode("^",$read)[1]);//or urldecode(preg_split('@(?=reader_name)@',$read)[1]); demo https://ideone.com/lfEn40
$post = [];
foreach (explode('&', $string) as $chunk) {
    $param = explode("=", $chunk); 
    $post[$param[0]] = isset($param[1])?$param[1]:'';      
}
$readerName = $post['mac_address'];
//....

更改文件生成器功能中的以下行

fwrite($fp, date("l F d, Y, h:i A") . "^" . $rawPostData . "\n"); 
//.....................................^ change here the coma into ^

Answer 2

$ _ POST 设置为：内容类型：application / x-www-form-urlencoded 换句话说，对于标准网络表单。

是基于任何表单/帖子创建的日志文件？如果没有那么你就不会从$ _POST变量中获取数据，所以你需要从文件读取数据，而不是像@madalin那样的$ _POST变量

PHP：从文本文件中获取每个POST数据并将其插入数据库

2 个答案: