Question

可能重复：
CSV parser in C++

您好，我想在c ++中将csv文件读入2D数组。想象一下我的csv文件是： A，B，C d，E，F 有人会帮我制作一张2x3的桌子吗？谢谢，

Answer 1

哦，好吧，这就是做的事情。它专门满足您的需求，但它的工作原理。我还提到了BOOST技术，但这对你来说可能太先进了......

#ifndef BOOST_METHOD
std::string popToken(std::string& text, const std::string& delimiter)
{
    std::string result = "";
    std::string::size_type pos = text.find(delimiter);
    if (pos != std::string::npos) {
        result.assign(text.begin(), text.begin() + pos);
        text.erase(text.begin(), text.begin() + pos + delimiter.length());        
    } else {
        text.swap(result);
    }
    return result;
}
#endif

void readCSV()
{
    const size_t rows = 2;
    const size_t cols = 3;
    std::string data[rows][cols];
    std::ifstream fin;

    fin.open("csv.txt");
    if (! fin.fail()) {
        std::string line;
        while (! fin.eof()) {
            fin >> line;
#ifdef BOOST_METHOD
            boost::tokenizer<boost::escaped_list_separator<char> > tknzr(line, boost::escaped_list_separator<char>('\\', ',', '\"'));
            boost::tokenizer<boost::escaped_list_separator<char> >::iterator it = tknzr.begin();
            for (size_t row = 0; row < rows && it != tknzr.end(); row++) {
                for (size_t col = 0; col < cols &&  it != tknzr.end(); col++, ++it) {
                    data[row][col] = *it;
                    std::cout << "(" << row << "," << col << ")" << data[row][col] << std::endl;
                }
            }
#else
            for (size_t row = 0; row < rows && line.length(); row++) {
                for (size_t col = 0; col < cols && line.length(); col++) {
                    data[row][col] = popToken(line, ",");
                    std::cout << "(" << row << "," << col << ")" << data[row][col] << std::endl;
                }
            }
#endif
        }
        fin.close();
    }
}

将csv文件读入c ++

1 个答案: