Question

我的数据如下

11111 22222 33333 44444                       55555           66666

我想输出数据如下

11111,22222,3333,4444                       ,55555           ,66666

我尝试使用逗号转换空格来使用tr命令，但是在4444 OR 55555之后得到所有逗号。注意：4444和5555之间有很多空格。是否可以在6号，12号填充空格，17号，46号等用逗号列？

Answer 1

这不就是你要找的吗？（猜测你想要的输出中缺少4个是错字）

sed -E 's/ ([0-9])/,\1/g' data

（如果你在Mac上，请使用-r代替-E。

Answer 2

如果您的实际Input_file与显示的示例相同，那么以下内容也可能对您有所帮助。

awk '{gsub(/ [0-9]+/,",&");gsub(/, /,",")} 1'   Input_file

输出如下。

11111,22222,33333,44444                      ,55555          ,66666

上述命令的说明：

awk '{
gsub(/ [0-9]+/,",&"); ##gsub is awk utility to substitute things, so its format is gsub(regex_for_strings_to_be_replaced,with_whom_it_should_be_replaced,variable/line). So here I am substituting globally space then all digits(continuous ones) with a comma and (matched regex itself, which is space then all digits(continuous ones)).
gsub(/, /,",")        ##Using gsub again here to replace comma then space(, ) with only comma(,), to get the output into same shape in which OP has asked, it will remove space between command and digits which was created in above command.
}
1                     ##awk works on method of condition then action, so here I am making condition as TRUE by mentioning 1 and not mentioning any action so be default print action will happen, print of current line.
' Input_file          ##Mentioning Input_file name here.

如何使用shell在每第n列插入分隔符

2 个答案: