使用SQL显示特定时段的平均小时数

Question

我试图显示3个时段的平均休假日和病假。

到目前为止，我有这个SQL查询：

SELECT AVG(VACATIONHOURS) AS 'Vacation hours', AVG(SICKLEAVEHOURS) AS 'SICK DAYS'
FROM HUMANRESOURCES.EMPLOYEE E
WHERE E.BIRTHDATE BETWEEN '01-01-1960' AND '12-31-1969'
UNION ALL
SELECT AVG(VACATIONHOURS) AS 'VACATION', AVG(SICKLEAVEHOURS) AS 'SICK DAYS'
FROM HUMANRESOURCES.EMPLOYEE E
WHERE E.BIRTHDATE BETWEEN '01-01-1970' AND '12-31-1979'
UNION ALL
SELECT AVG(VACATIONHOURS) AS 'VACATION', AVG(SICKLEAVEHOURS) AS 'SICK DAYS'
FROM HUMANRESOURCES.EMPLOYEE E
WHERE E.BIRTHDATE BETWEEN '01-01-1980' AND '12-31-1989'
;

我的输出只有2列生病和休假日，3行有数字。

我的问题是如何添加显示年份的第3列？

我需要为报告生成器，因此我可以正确地表示该信息

Answer 1

我希望您希望在where子句中添加年份，然后添加max（years）

SELECT AVG(VACATIONHOURS) AS 'Vacation hours', 
       AVG(SICKLEAVEHOURS) AS 'SICK DAYS', 
       max('1960 to 1969')
 FROM HUMANRESOURCES.EMPLOYEE E
WHERE E.BIRTHDATE BETWEEN '01-01-1960' AND '12-31-1969'

Answer 2

我建议你把这些分组。我会这样做：

SELECT CONCAT(YEAR(BIRTHDATE), 's') as decade,
       AVG(VACATIONHOURS) AS `Vacation hours`,
       AVG(SICKLEAVEHOURS) AS `SICK DAYS`
FROM HUMANRESOURCES.EMPLOYEE E
GROUP BY decade
ORDER BY decade;