Question

我尝试做的是从另一个组件打开一个模态，但是当TypeError: Cannot create property 'validator' on string 'test1'加载时我会一直收到此错误component1.html，因为包含了childModal。如何摆脱这些错误并正确实施？

component1.html

<button type="button" class="btn btn-outline-primary btn-lg" (click)="modal.showModal()">Test
......
<child-modal #childModal ></child-modal>

component1.ts

 @ViewChild('childModal') childModal: ModalComponent;

modal.html

<div bsModal #childModal="bs-modal" class="modal fade" tabindex="-1" role="dialog>
    <div class="modal-dialog modal-lg">
      <div class="modal-content">
          <input type="text" formControl="test1">
          <input type="text" formControl="test2">
          </div>
     </div>
</div>

modal.component.ts

constructor(private modalService: BsModalService) {
    this.form = new FormGroup({
      'test':                     new FormControl(),
      'test2':                    new FormControl()
      }) 
 }

Answer 1

如果您尝试从另一个组件打开模态组件，那么这是使用ngx-bootstrap执行此操作的正确方法：

import { Component } from '@angular/core';
import { BsModalService } from 'ngx-bootstrap/modal';
import { BsModalRef } from 'ngx-bootstrap/modal/modal-options.class';

/* This is the Component from which we open the Modal Component */
@Component({
  selector: 'my-component',
  templateUrl: './service-component.html'
})
export class MyComponent {
  bsModalRef: BsModalRef;
  constructor(private modalService: BsModalService) {}

  public openModalWithComponent() {
    /* this is how we open a Modal Component from another component */
    this.bsModalRef = this.modalService.show(ModalContentComponent);
  }
}

/* This is the Modal Component */
@Component({
  selector: 'child-modal',
  template: `
    <div class="modal-header">
      <h4 class="modal-title pull-left">Title</h4>
      <button type="button" class="close pull-right" aria-label="Close" (click)="bsModalRef.hide()">
        <span aria-hidden="true">&times;</span>
      </button>
    </div>
    <div class="modal-body">
      ...
    </div>
    <div class="modal-footer">
      <button type="button" class="btn btn-default" (click)="bsModalRef.hide()">Close</button>
    </div>
  `
})
export class ChildModalComponent {
  constructor(public bsModalRef: BsModalRef) {}
}

调用模态的组件的模板：

<button type="button" class="btn btn-primary" (click)="openModalWithComponent()">Create modal with component</button>

所以你应该不在模板中包含模态组件，如下所示：

 <child-modal #childModal ></child-modal>

官方文件：

https://valor-software.com/ngx-bootstrap/#/modals#service-component

Answer 2

If you use same component then, 

HTML #
    <button (click)="openModalWithComponent()">open</button>

    // for display purpose
    <ng-template #template>
      <div class="modal-body">
      </div>
    </ng-template>

COMPONENT #
import { BsModalRef } from 'ngx-bootstrap/modal/bs-modal-ref.service';
import { BsModalService } from 'ngx-bootstrap/modal';
import { ViewChild, ElementRef } from '@angular/core';

      bsModalRef: BsModalRef;
constructor(private modalService: BsModalService) {}
      @ViewChild('template') elementView: ElementRef;
    openModalWithComponent() {    
        this.bsModalRef = this.modalService.show(this.elementView);
        // this.bsModalRef.content.closeBtnName = 'Close';
        // (click)="bsModalRef.hide()"

    }

Answer 3

您只需要将子组件添加到模块中的entryComponents中，如下所示：

entryComponents: [
    childComponent
]

对我有用

ngx-bootstrap如何从另一个组件打开模态？

3 个答案: