Question

我希望在下面的代码中添加一个IF语句，该代码将检查来自Prestige的＆＃34; Medicaid＃是否属于＆＃34; [Medicaid＃from Prestige]＆＃34;细胞

如果找到了，我想让它显示＆＃34; TRUE＆＃34;如果不是那么＆＃34; FALSE＆＃34;我不确定如何在代码本身内执行此操作。我确定我忽略了一些东西，但是已经查看了代码，并且在我的代码需要的情况下，我们无法找到一种确切的方法来提取代码。

SELECT DISTINCT
         pml.NPI AS [PML NPI] -- COALESCE will get first non null value
    ,pml.[Provider Name] as [Prov. Name from PML]
    ,pp.npi as [Prestige NPI]
    ,pp.last_name as [Last name (Prestige)]
    ,pp.first_name as [First name (Prestige)]
    ,case
        when pp.provider_type = 'i' then 'Individual'
      when pp.provider_type = 'g' then 'Group'
        else 'UNDEFINED'
    end as [Provider type]
    ,pp.Group_name as [Group name (Prestige)]
    ,case
        when pml.[Current Medicaid Enrollment Status A Active I Inactive E Ineligible] = 'A' then 'Active'
         when pml.[Current Medicaid Enrollment Status A Active I Inactive E Ineligible] = 'I' then 'Inactive'
      when pml.[Current Medicaid Enrollment Status A Active I Inactive E Ineligible] = 'E' then 'Ineligible'
        else 'UNDEFINED'
    end as [Medicaid Status]
    ,pml.[Florida Medicaid Provider ID] as [Medicaid # from PML]
    ,pp.medicaid_number as [Medicaid # from Prestige]
    ,case 
      when pml.[Florida Medicaid Provider ID]  like '*'+pp.medicaid_number+'*' then 'TRUE'
      else 'FALSE'
    end as [Medicaid match?]

    FROM [DWH].[dbo].[PML] as pml -- Full join shows all records, null will show for missing records
        FULL JOIN [DWH].[dbo].[PrestigeProviders] as pp  on pml.NPI = pp.npi
    WHERE (pml.npi IS not NULL AND pp.npi IS not NULL) -- only show when one side of the join fails

调整我的代码，并获取下表（截断相关数据并防止HIPAA违规）：

Medicaid # from PML   Medicaid # from Prestige   Medicaid match?
18739600              018739600                  FALSE
13104200              013104200                  FALSE
9851900               009851900                  FALSE
10331600              009851900                  FALSE

Answer 1

LIKE的通配符为%，而不是*。
标准SQL中的串联符号为||而非+。但它是SQL Server中的+。
应该是＆＃39; 009851900＆＃39;喜欢＆＃39;％9851900％＆＃39;，不是＆＃39; 9851900＆＃39;喜欢＆＃39;％009851900％＆＃39;。

因此：

case when pp.medicaid_number like '%' + pml.[Florida Medicaid Provider ID] + '%' 
  then 'TRUE'
  else 'FALSE'
end as [Medicaid match?]

SQL - 查询中的IF语句

1 个答案: