我想合并3个spannable对象。这段代码工作正常:
Spannable s1 = new SpannableStringBuilder("bold");
s1.setSpan(new StyleSpan(android.graphics.Typeface.BOLD), 0, s1.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
Spannable s2 = new SpannableStringBuilder("not");
Spannable s3 = new SpannableStringBuilder("BOLD");
s3.setSpan(new StyleSpan(android.graphics.Typeface.BOLD), 0, s3.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
finishSpan = (Spanned) TextUtils.concat(s1,s2);
finishSpan = (Spanned) TextUtils.concat(finishSpan,s3);
/////////////////////////////////////////////// ///////
或finishSpan = (Spanned) TextUtils.concat(s1,s2,s3);
我有相同的代码但是当我合并3个对象时,结果是错误的。 我已经检查过某些元素的类型是否正确 beginningOfModifiedSpannable为粗体,selectionSpannable为normal,endOfModifiedSpannable为粗体 但他们的合并是错误的。只有结果字符串的最后一部分是粗体。为什么会这样?我上面有相同的代码,效果很好!
Spannable str = contentText.getText();
Spannable selectionSpannable = new SpannableStringBuilder(str, selectionStart, selectionEnd);
StyleSpan[] ss = selectionSpannable.getSpans(0, selectionSpannable.length(), StyleSpan.class);
boolean exists = false;
for (int i = 0; i < ss.length; i++) {
if (ss[i].getStyle() == android.graphics.Typeface.BOLD){
selectionSpannable.removeSpan(ss[i]);
exists = true;
}
}
if (!exists){
str.setSpan(new StyleSpan(android.graphics.Typeface.BOLD), selectionStart, selectionEnd, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
}
else {
Spannable endOfModifiedSpannable = new SpannableStringBuilder(str, selectionEnd, contentText.getText().length());
Spannable beginningOfModifiedSpannable = new SpannableStringBuilder(str, 0, selectionStart);
Spanned finishSpan = null;
if(beginningOfModifiedSpannable.length() > 0) {
if(endOfModifiedSpannable.length() > 0) {
finishSpan = (Spanned) TextUtils.concat(beginningOfModifiedSpannable,selectionSpannable);
finishSpan = (Spanned) TextUtils.concat(finishSpan,endOfModifiedSpannable);
}
else {
finishSpan = (Spanned) TextUtils.concat(beginningOfModifiedSpannable,selectionSpannable);
}
}
else {
if(endOfModifiedSpannable.length() > 0) {
finishSpan = (Spanned) TextUtils.concat(selectionSpannable,endOfModifiedSpannable);
}
else {
finishSpan = selectionSpannable;
}
}
contentText.setText(finishSpan);
我再说一遍,我已经检查过3个部分是真的。例如。我有3个部分: Hel lo,wor ld
我注意到第一次合并是正确的:
finishSpan = (Spanned) TextUtils.concat(beginningOfModifiedSpannable,selectionSpannable);
看起来像 Hel lo,wor
但第二个错误
finishSpan = (Spanned) TextUtils.concat(finishSpan,endOfModifiedSpannable);
或合并错误:
finishSpan = (Spanned) TextUtils.concat(finishSpan,selectionSpannable,endOfModifiedSpannable);
错误字符串的结果是: 您好,WO的 RLD
但真正的结果必须是这样的:
赫尔 LO,世界
无意义!
答案 0 :(得分:16)
问题是你很可能对两个部分使用相同的CharacterStyle实例,第1和第3部分。每次向Spannable对象添加样式时都需要使用新实例。
e.g。
SpannableStringBuilder ssb = new SpannableStringBuilder("Hello,world");
CharacterStyle c = new StyleSpan(Typeface.BOLD);
ssb.setSpan(c, 0, 3, 0);
ssb.setSpan(c, 9, 11, 0);
这将导致Hello,Wor ld
要获得正确的结果,您必须执行以下操作:
SpannableStringBuilder ssb = new SpannableStringBuilder("Hello,world");
CharacterStyle c = new StyleSpan(Typeface.BOLD);
CharacterStyle c2 = new StyleSpan(Typeface.BOLD);
ssb.setSpan(c, 0, 3, 0);
ssb.setSpan(c2, 9, 11, 0);
答案 1 :(得分:0)
扩展@tagtraeumer的建议,这是另一个需要额外摆弄的情况。
显然,将相同的样式实例应用于不同的SpannableStringBuilder对象也不起作用。
例如。以下代码段仅将 mystyle 应用于 txt1 在文本框中。出于任何原因 mystyle 都会从 txt2
中删除TextView tv;
StyleSpan mystyle = new StyleSpan(Typeface.BOLD);
SpannableStringBuilder txt1 = new SpannableStringBuilder(somestring);
txt1.setSpan(mystyle,0,5,Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
SpannableStringBuilder txt2 = new SpannableStringBuilder(anotherstring);
txt2.setSpan(mystyle,0,5,Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
tv.setText(TextUtils.concat(txt1, txt2));
为了能够看到所有Spannable对象出现的样式,请创建唯一的样式对象,并将其应用于每个Spannable String Builder对象
TextView tv;
StyleSpan mystyle1 = new StyleSpan(Typeface.BOLD);
StyleSpan mystyle2 = new StyleSpan(Typeface.BOLD);
SpannableStringBuilder txt1 = new SpannableStringBuilder(somestring);
txt1.setSpan(mystyle1,0,5,Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
SpannableStringBuilder txt2 = new SpannableStringBuilder(anotherstring);
txt2.setSpan(mystyle2,0,5,Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
tv.setText(TextUtils.concat(txt1, txt2));