Question

我们正在制作BINGO游戏，其中我们有25个按钮，我创建了他们的对象和一个存储它们的数组。现在我需要在多个函数中访问这些按钮对象。我在哪里准确地声明那些按钮的对象？此外，我在onCreate（）之后定义了我班级中的所有函数。我需要访问show（），acceptNum（），client_row（）中的那些按钮对象，我应该在哪里以及如何声明它？请帮忙！

public class bingo extends AppCompatActivity
{
@Override
protected void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_bingo);
}
    Button b1 = (Button) findViewById(R.id.button);
    Button b2 = (Button) findViewById(R.id.button2);
    Button b3 = (Button) findViewById(R.id.button3);
    Button b4 = (Button) findViewById(R.id.button4);
    Button b5 = (Button) findViewById(R.id.button5);
    Button b6 = (Button) findViewById(R.id.button6);
    Button b7 = (Button) findViewById(R.id.button7);
    Button b8 = (Button) findViewById(R.id.button8);
    Button b9 = (Button) findViewById(R.id.button9);
    Button b10 = (Button) findViewById(R.id.button10);
    Button b11 = (Button) findViewById(R.id.button11);
    Button b12 = (Button) findViewById(R.id.button12);
    Button b13 = (Button) findViewById(R.id.button13);
    Button b14 = (Button) findViewById(R.id.button14);
    Button b15 = (Button) findViewById(R.id.button15);
    Button b16 = (Button) findViewById(R.id.button17);
    Button b17 = (Button) findViewById(R.id.button18);
    Button b18 = (Button) findViewById(R.id.button19);
    Button b19 = (Button) findViewById(R.id.button20);
    Button b20 = (Button) findViewById(R.id.button21);
    Button b21 = (Button) findViewById(R.id.button22);
    Button b22 = (Button) findViewById(R.id.button23);
    Button b23 = (Button) findViewById(R.id.button24);
    Button b24 = (Button) findViewById(R.id.button25);
    Button b25 = (Button) findViewById(R.id.button26);

    Button butt[] = {b1, b2, b3, b4, b5, b6, b7, b8, b9, b10, b11, b12, b13, 
 b14, b15, b16, b17, b18, b19, b20, b21, b22, b23, b24, b25};

public void show()
{...}

public void acceptNum()
{...}

public void client_row()
{...}

}

}//closing class

Answer 1

你在onCreate之外声明你的按钮并在OnCreate中初始化它：

public class bingo extends AppCompatActivity{
Button b1;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_bingo);

     b1 =  (Button) findViewById(R.id.button);
}



public void show()
{...}

public void acceptNum()
{...}

public void client_row()
{...}


}//closing class

Answer 2

也许尝试将它们作为类成员实现：

public class Bingo extends AppCompatActivity {

    private Button b1;
    // more buttons here

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_bingo);

        b1 = (Button) findViewById(R.id.button);
        // other findViewByIds here

    }

    public void someOtherMethod() {
        // do something with the buttons
    }
}

android - 如果在onCreate（）中声明，如何访问多个函数中的按钮对象

2 个答案: