使用我的代码，我读取了JSON数据的值并插入到数组
中def retrive_json():
with open('t_v1.json') as json_data:
d = json.load(json_data)
array = []
for i in d['ride']:
origin_lat = i['origin']['lat']
origin_lng = i['origin']['lng']
destination_lat = i['destination']['lat']
destination_lng = i['destination']['lng']
array.append([origin_lat,origin_lng,destination_lat,destination_lng])
return array
结果数组是：
[[39.72417, -104.99984, 39.77446, -104.9379], [39.77481, -104.93618, 39.6984, -104.9652]]
如何将每个数组的每个元素写入csv中的特定字段？ 我试过这样的方式：
wrt = csv.writer(open(t_.csv', 'w'), delimiter=',',lineterminator='\n')
for x in jjson:
wrt.writerow([x])
但每个数组的值都存储在一个字段中 如何解决它并在一个字段中写每个？
这是我的json文件：
{
"ride":[
{
"origin":{
"lat":39.72417,
"lng":-104.99984,
"eta_seconds":null,
"address":""
},
"destination":{
"lat":39.77446,
"lng":-104.9379,
"eta_seconds":null,
"address":null
}
},
{
"origin":{
"lat":39.77481,
"lng":-104.93618,
"eta_seconds":null,
"address":"10 Albion Street"
},
"destination":{
"lat":39.6984,
"lng":-104.9652,
"eta_seconds":null,
"address":null
}
}
]
}
答案 0 :(得分：1)
这可能会有所帮助：
import json
import csv
def retrive_json():
with open('data.json') as json_data:
d = json.load(json_data)
array = []
for i in d['ride']:
origin_lat = i['origin']['lat']
origin_lng = i['origin']['lng']
destination_lat = i['destination']['lat']
destination_lng = i['destination']['lng']
array.append([origin_lat,origin_lng,destination_lat,destination_lng])
return array
res = retrive_json()
csv_cols = ["orgin_lat", "origin_lng", "dest_lat", "dest_lng"]
with open("output_csv.csv", 'w') as out:
writer = csv.DictWriter(out, fieldnames=csv_cols)
writer.writeheader()
for each_list in res:
d = dict(zip(csv_cols,each_list))
writer.writerow(d)
生成的输出csv是：
orgin_lat,origin_lng,dest_lat,dest_lng
39.72417,-104.99984,39.77446,-104.9379
39.77481,-104.93618,39.6984,-104.9652
答案 1 :(得分：1)
我们说我们有这个：
import java.awt.BorderLayout;
import java.awt.Color;
import java.awt.Font;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;
import javax.imageio.ImageIO;
import javax.swing.ImageIcon;
import javax.swing.JButton;
import javax.swing.JFileChooser;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JScrollPane;
import javax.swing.SwingUtilities;
public class Main {
public static JFrame f = new JFrame();
// Pointless, applets are deprecated
// Besides, this isn't how you use them
//public static JApplet a = new JApplet();
public static JPanel p = new JPanel();
public static JButton b = new JButton();
public static JScrollPane pane = new JScrollPane(p, JScrollPane.VERTICAL_SCROLLBAR_ALWAYS, JScrollPane.HORIZONTAL_SCROLLBAR_ALWAYS);
public static JLabel gameimage;
public static void main(String[] args) {
SwingUtilities.invokeLater(new Runnable() {
@Override
public void run() {
f.setSize(1000, 800);
//a.setBounds(0, 0, 1000, 800);
//a.setVisible(true);
//a.setBackground(Color.WHITE);
// Pointless, the layout manager of the JScrollPane
// will make these choices
//p.setBounds(0, 0, 1000, 800);
p.setVisible(true);
p.setBackground(Color.WHITE);
// !! This is root of your problem !!
//p.setLayout(null);
p.setLayout(new BorderLayout());
// Pointless, it already is
//p.setOpaque(true);
// Pointless, you don't do anything with the returned value
//pane.getVerticalScrollBar();
//pane.getHorizontalScrollBar();
// Pointless, it already is
//pane.setVisible(true);
// Pointless
//b.setBounds(955, 0, 40, 30);
b.setText("+");
b.setFont(new Font("Times Roman", Font.BOLD, 30));
// Pointless
//b.setVisible(true);
b.setBorder(javax.swing.BorderFactory.createLineBorder(Color.WHITE));
b.setBackground(Color.WHITE);
b.setForeground(Color.GREEN);
b.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
JFileChooser file = new JFileChooser();
file.setFileSelectionMode(JFileChooser.FILES_AND_DIRECTORIES);
file.setAcceptAllFileFilterUsed(true);
if (file.showOpenDialog(null) == JFileChooser.APPROVE_OPTION) {
int width;
int height;
File f = file.getSelectedFile();
try {
BufferedImage bimg = ImageIO.read(new File(f.getAbsolutePath()));
width = bimg.getWidth();
height = bimg.getHeight();
String fname = f.getAbsolutePath();
if (gameimage != null) {
p.remove(gameimage);
}
gameimage = new JLabel("", new ImageIcon(fname), JLabel.CENTER);
gameimage.setSize(width, height);
gameimage.setOpaque(true);
//a.revalidate();
//a.repaint();
//p.removeAll();
// Not really what you want to do right now
// Besides, if you use a null layout, it won't do anything
//p.revalidate();
//p.repaint();
//pane.revalidate();
//pane.repaint();
//p.setSize(width, height);
p.add(gameimage);
//p.add(b);
//p.add(pane);
// Presumaly, pane should alredy be added to a container
//a.getContentPane().add(pane);
p.revalidate();
p.repaint();
} catch (IOException ioe) {
}
} else {
System.out.println("not working");
}
}
});
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
// Not what you want to call here
//f.setVisible(true);
// Probably not the best idea right now
f.setResizable(false);
//f.add(a);
//a.add(p);
// Good idea to add the scollpane to the container
f.add(pane);
p.add(b, BorderLayout.SOUTH);
f.setVisible(true);
}
});
}
}
这是一个熊猫解决方案：
jsonstring = """{
"ride":[
{
"origin":{
"lat":39.72417,
"lng":-104.99984,
"eta_seconds":null,
"address":""
},
"destination":{
"lat":39.77446,
"lng":-104.9379,
"eta_seconds":null,
"address":null
}
},
{
"origin":{
"lat":39.77481,
"lng":-104.93618,
"eta_seconds":null,
"address":"10 Albion Street"
},
"destination":{
"lat":39.6984,
"lng":-104.9652,
"eta_seconds":null,
"address":null
}
}
]
}"""
返回：
import pandas as pd
import json
# Load json to dataframe
df = pd.DataFrame(json.loads(jsonstring)["ride"])
# Create the new columns
df["o1"] = df["origin"].apply(lambda x: x["lat"])
df["o2"] = df["origin"].apply(lambda x: x["lng"])
df["d1"] = df["destination"].apply(lambda x: x["lat"])
df["d2"] = df["destination"].apply(lambda x: x["lng"])
#export
print(df.iloc[:,2:].to_csv(index=False, header=True))
#use below for file
#df.iloc[:,2:].to_csv("output.csv", index=False, header=True)
简明回答：
o1,o2,d1,d2
39.72417,-104.99984,39.77446,-104.9379
39.77481,-104.93618,39.6984,-104.9652
或者，也许是最易读的解决方案：
import pandas as pd
import json
with open('data.json') as json_data:
d = json.load(json_data)
df = pd.DataFrame(d["ride"])
df["o1"],df["o2"] = zip(*df["origin"].apply(lambda x: (x["lat"],x["lng"])))
df["d1"],df["d2"] = zip(*df["destination"].apply(lambda x: (x["lat"],x["lng"])))
df.iloc[:,2:].to_csv("t_.csv",index=False,header=False)
答案 2 :(得分：0)
对我来说，看起来你有一个阵列数组，你想要各个元素。因此，您需要使用嵌套的for循环。你当前的for循环正在获取每个数组，然后将每个数组拆分成你想要循环遍历它们的元素。我建议这样的事情：
for x in jjson:
for y in x:
wrt.writerow([y])
显然你可能想要更新你的包围等等，这只是让你知道如何解决你的问题。
让我知道它是怎么回事！
答案 3 :(得分：0)
为什么csv - 图书馆？
array = [[1, 2, 3, 4], [5, 6, 7, 8]]
with open('test.csv', 'w') as csv_file :
csv_file.write("# Header Info\n" \
"# Value1, Value2, Value3, Value4\n") # The header might be optional
for row in array :
csv_file.write(",".join(row) + "\n")