Question

我这是MySQL中的三个表。

艺术家姓名表（m）带有产品iformations的表，在这种情况下图片地址（p）具有艺术家ID和产品ID的表。（PMX）

我正在尝试将他们加在一起，所以我为每个艺术家获得了一行。 1位艺术家的 p 表中有几张图片。我添加了一个名为mf_prior的列，其中是图像的数量（用户自己分配数字并选择他想要在前端显示的3个图像）。我正在寻找Letters的艺术家（制造商）。 “M”

我的想法是，我想得到

manufacturer_id | mf_name | img1_id | img1_address | img2_id | img2_address | img3_id | img3_address

我正在

manufacturer_id1 | mf_name1 | img1_id | img1_address | NULL | NULL | NULL | NULL
manufacturer_id1 | mf_name1 | NULL | NULL | img2_id | img2_address | NULL | NULL
manufacturer_id1 | mf_name1 | NULL | MULL | NULL | NULL | img3_id | img3_address

我有这个MySQL SELECT：

SELECT
 m.manufacturer_id ,
 m.mf_name ,
 p1.product_id AS pimg1 ,
 p1.product_full_image AS p1 ,
 p2.product_id AS pimg2 ,
 p2.product_full_image AS p2 ,
 p3.product_id AS pimg3 ,
 p3.product_full_image AS p3 
FROM
 jos_vm_product_mf_xref AS pmx 
JOIN
 jos_vm_manufacturer AS m ON m.manufacturer_id = pmx.manufacturer_id 
JOIN
 jos_vm_product AS p1 ON p1.product_id = pmx.product_id AND p1.mf_prior = 1
JOIN
 jos_vm_product AS p2 ON p2.product_id = pmx.product_id AND p2.mf_prior = 2
JOIN
 jos_vm_product AS p3 ON p3.product_id = pmx.product_id AND p3.mf_prior = 3

WHERE
 m.mf_chars = 'm'

因此我得到3行，并且在某些地方我得到NULL - 如上所示

也许任何人都可以帮我解决这个问题 - 编写一个更好的SELECT或用PHP结果制作smth

Answer 1

所以我做到了。

新的SQL SELECT如下所示：

SELECT
    m.manufacturer_id ,
    m.mf_name ,
    p1.product_id AS pimg1 ,
    p1.product_full_image AS p1 ,
    p2.product_id AS pimg2 ,
    p2.product_full_image AS p2 ,
    p3.product_id AS pimg3 ,
    p3.product_full_image AS p3 
FROM
    jos_vm_product_mf_xref AS pmx 
JOIN
    jos_vm_manufacturer AS m ON m.manufacturer_id = pmx.manufacturer_id 
JOIN
    jos_vm_product AS p1 ON p1.product_id = pmx.product_id AND p1.mf_prior = 1
JOIN
    jos_vm_product AS p2 ON p1.product_id = pmx.product_id AND p2.mf_prior = 2
JOIN
    jos_vm_product AS p3 ON p1.product_id = pmx.product_id AND p3.mf_prior = 3
WHERE
    m.mf_chars = 'm'

事情是改变前线：

加入

jos_vm_product AS p3 ON p1.product_id = pmx.product_id AND p3.mf_prior = 3

Answer 2

SELECT 
    ts.manufacturer_id ,
    tb1.mf_name ,
    ts.S1ID AS V1ID,
    tb21.product_full_image AS V1 ,
    ts.S2ID AS V2ID,
    tb22.product_full_image AS V2 ,
    ts.S3ID AS V3ID,
    tb23.product_full_image AS V3 
FROM
    (
        SELECT 
            tbs.manufacturer_id AS manufacturer_id,
            MAX(S1) AS sn1,
            MAX(S1ID) AS S1ID ,
            MAX(S2) AS sn2,
            MAX(S2ID) AS S2ID ,
            MAX(S3) AS sn3 ,
            MAX(S3ID) AS S3ID 
        FROM 
            (
                SELECT 
                    vs.manufacturer_id ,
                    CASE
                        WHEN t2.mf_prior = 1 THEN 1 ELSE 0
                    END AS S1 ,
                    CASE
                        WHEN t2.mf_prior = 1 THEN t2.product_id ELSE 0
                    END AS S1ID ,
                    CASE
                        WHEN t2.mf_prior = 2 THEN 2 ELSE 0
                    END AS S2 ,
                    CASE
                        WHEN t2.mf_prior = 2 THEN t2.product_id ELSE 0
                    END AS S2ID ,
                    CASE
                        WHEN t2.mf_prior = 3 THEN 3 ELSE 0
                    END AS S3 ,
                    CASE
                        WHEN t2.mf_prior = 3 THEN t2.product_id ELSE 0
                    END AS S3ID 
                FROM
                    jos_vm_product AS t2
                JOIN
                    jos_vm_product_mf_xref AS vs ON vs.product_id = t2.product_id
            ) tbs
        GROUP BY
            tbs.manufacturer_id
    ) ts
JOIN
    jos_vm_manufacturer AS tb1 ON ts.manufacturer_id = tb1.manufacturer_id 
LEFT JOIN
    jos_vm_product AS tb21 ON ts.S1ID = tb21.product_id AND ts.sn1 = tb21.mf_prior 
LEFT JOIN
    jos_vm_product AS tb22 ON ts.S2ID = tb22.product_id AND ts.sn2 = tb22.mf_prior 
LEFT JOIN
    jos_vm_product AS tb23 ON ts.S3ID = tb23.product_id AND ts.sn3 = tb23.mf_prior

这是对我的问题的正确和正确解决 - 我正在使用它并且工作正常，前一个问题不是100％正确，在某些情况下它正在崩溃。但这一个就是那个!!!

将MySQL中的信息与1行对齐

2 个答案: