Question

有两个相应的一对一关系列表。

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy"]
scores = [1,1,0.8,0.2,0.4,0.1,0.6]

我想要显示得分超过0.5且显示在1行中的人：

Peter (1 point), David (1 point), Kate (0.8 point), Judy (0.6 point)

我尝试的是：

import operator

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy"]
scores = [1,1,0.8,0.2,0.4,0.1,0.6]

dictionary = dict(zip(names, scores))

dict_sorted = sorted(dictionary.items(), key=operator.itemgetter(1), reverse=True)

print dict_sorted

它给出了：

[('Peter', 1), ('David', 1), ('Kate', 0.8), ('Judy', 0.6), ('Kit', 0.4), ('Lucy', 0.2), ('Jason', 0.1)]

如何才能进一步获得想要的结果？注意：需要从大到小排序结果。

2个用于测试目的的较长列表：

names = ["Olivia","Charlotte","Khaleesi","Cora","Isla","Isabella","Aurora","Amelia","Amara","Penelope","Audrey","Rose","Imogen","Alice","Evelyn","Ava","Irma","Ophelia","Violet"]
scores = [1.0, 1.0, 0.8, 0.2, 0.2, 0.4, 0.2, 0.0, 1.0, 0.2, 0.4, 0.2, 1.0, 0.0, 0.8, 0.0, 1.0, 0.0, 0.6]

Answer 1

这应该可以解决问题：

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy", "Mark", "John", "Irene"]
scores = [1,1,0.8,0.2,0.4,0.1,0.6,0.7,0.3,1.2]

print(', '.join('{} ({} points)'.format(name, points) for name, points in sorted(zip(names, scores), key=__import__('operator').itemgetter(1), reverse=True) if points > 0.5))

输出：

Irene (1.2 points), David (1 points), Peter (1 points), Kate (0.8 points), Mark (0.7 points), Judy (0.6 points)

Answer 2

您可以在一行中执行此操作，但如果您分阶段执行此操作则更容易阅读。首先选择分数大于阈值的项目，然后对它们进行排序。

import operator

names = ["Olivia","Charlotte","Khaleesi","Cora","Isla","Isabella","Aurora","Amelia","Amara","Penelope","Audrey","Rose","Imogen","Alice","Evelyn","Ava","Irma","Ophelia","Violet"]
scores = [1.0, 1.0, 0.8, 0.2, 0.2, 0.4, 0.2, 0.0, 1.0, 0.2, 0.4, 0.2, 1.0, 0.0, 0.8, 0.0, 1.0, 0.0, 0.6]

threshold = 0.5
lst = [(name, score) for name, score in zip(names, scores) if score > threshold]
lst.sort(reverse=True, key=operator.itemgetter(1))
print(lst)

<强>输出

[('Olivia', 1.0), ('Charlotte', 1.0), ('Amara', 1.0), ('Imogen', 1.0), ('Irma', 1.0), ('Khaleesi', 0.8), ('Evelyn', 0.8), ('Violet', 0.6)]

这是单线版：

print(sorted(((name, score) for name, score in zip(names, scores) if score > 0.5), reverse=True, key=operator.itemgetter(1)))

Answer 3

如果您想要排序的输出，也可以使用OrderedDict表单collections模块。

from collections import OrderedDict

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy"]
scores = [1,1,0.8,0.2,0.4,0.1,0.6]

dict_sorted = OrderedDict((k, v) for k, v in zip(names, scores) if v > 0.5)
print(', '.join('{} ({} points)'.format(k, v) for k, v in dict_sorted.items()))

打印： David (1 points), Peter (1 points), Kate (0.8 points), Judy (0.6 points)

Python按值（一个列表）对两个对应列表进行排序

3 个答案: