Question

在我的SQL Server表中，我有一个列Specialities，其值存储如下：

4' Tarps, 6' Tarps, 8' Tarps, Coil Racks, Edge Protectors, TWIC Card

即。值以逗号分隔的方式存储。

我想获取LIKE运算符中的列或该列中值匹配的任何其他运算符。

这就是我正在尝试的：

DECLARE @EquipmentServiceType nvarchar(max)

SET @EquipmentServiceType = '|Coil Racks|Hazmat|TWIC Card';
SET @EquipmentServiceType = REPLACE(@EquipmentServiceType,'''','')
SET @EquipmentServiceType = REPLACE(@EquipmentServiceType,'|',''',''')

select Specialities 
from CarrierData 
where Specialities like '%' + ''',''Coil Racks'',''Hazmat'',''TWIC Card''' + '%' 
    or Specialities like ',%' + ''',''Coil Racks'',''Hazmat'',''TWIC Card''' + ',%'

如何匹配SQL Server中的comma separated列？

这是表格图片： the table column is shown here

Answer 1

您应尝试更改数据库架构。

其他选项 - 您可以将CSV转换为表格，示例查询如下

DECLARE @strString VARCHAR(max)

SET @strString = '4'' Tarps, 6'' Tarps, 8'' Tarps, Coil Racks, Edge Protectors, TWIC Card'

DECLARE @x XML

SELECT
    @x = CAST('<Specialities><node>' +
     REPLACE(@strString, ',', '</node></Specialities><Specialities><node>') 
     + '</node></Specialities>' AS XML)

SELECT
    *
FROM (SELECT
        t.c.value('.', 'varchar(max)') AS Specialities
    FROM @x.nodes('//Specialities ') AS t (c)) AS final

--to declare WHERE Condition as needed, Uncomment the below  line

--WHERE final.Specialities LIKE '%Tarps%'

最终结果如下所示

+--------------+
| Specialities |
+--------------+
| 4' Tarps     |
|  6' Tarps    |
|  8' Tarps    |
+--------------+

修改

要搜索整个表行和列 - 下面是使用 COALESCE
在SQL语法中的更新
DECLARE @strString VARCHAR(max) --SET @strString = '4'' Tarps, 6'' Tarps, 8'' Tarps, Coil Racks, Edge Protectors, TWIC Card' --GETTING @strString directly from the table -- Assuming the column name is Specialities SELECT @strString = COALESCE(@strString + ',', '') + Specialities FROM <WriteYourTableNameHere> DECLARE @x XML SELECT @x = CAST('<Specialities><node>' + REPLACE(@strString, ',', '</node></Specialities><Specialities><node>') + '</node></Specialities>' AS XML) SELECT * FROM (SELECT t.c.value('.', 'varchar(max)') AS Specialities FROM @x.nodes('//Specialities ') AS t (c)) AS final --to declare WHERE Condition as needed, Uncomment the below line --WHERE final.Specialities LIKE '%%'

这将得到如下结果

+------------------+ | Specialities | +------------------+ | 4' Tarps | | 6' Tarps | | 8' Tarps | | Coil Racks | | Edge Protectors | | TWIC Card | | Partials | | None | | Partials | | TWIC Card | | 4' Tarps | | 6' Tarps | | Edge Protectors | +------------------+

结论虽然此解决方案运行良好，但在性能方面存在风险，表行中的逗号（，）无效。您需要根据数据的存储方式处理的那些

SQL Server中以逗号分隔的列值匹配

1 个答案: