我在django中创建URL视图时遇到问题。它给了我这个错误(ferrol是一个Space对象):
TypeError at /spaces/ferrol/
'str' object is not callable
Request Method: GET
Request URL: http://localhost:8000/spaces/ferrol/
Django Version: 1.2.3
Exception Type: TypeError
Exception Value:
'str' object is not callable
Exception Location: /usr/local/lib/python2.6/dist-packages/Django-1.2.3-py2.6.egg/django/core/handlers/base.py in get_response, line 100
以下是代码:
空间/ models.py
class Space(models.Model):
"""
Basic spaces model.
"""
name = models.CharField(_('Name'), max_length=100, unique=True)
description = models.TextField(_('Description'))
date = models.DateTimeField(auto_now_add=True)
logo = models.ImageField(upload_to='spaces/logos',
verbose_name=_('Logotype'))
banner = models.ImageField(upload_to='spaces/banners',
verbose_name=_('Banner'))
主要urls.py
urlpatterns = patterns('',
# Django administration
(r'^admin/', include(admin.site.urls)),
(r'^spaces/', include('apps.spaces.urls')),
(r'^static/(?P<path>.*)$', 'django.views.static.serve',
{'document_root': 'static'}),
)
if 'e_cidadania.apps.rosetta' in settings.INSTALLED_APPS:
urlpatterns += patterns('',
url(r'^rosetta/', include('apps.rosetta.urls')),
)
空间/ urls.py
urlpatterns = patterns('',
# Spaces
(r'^(?P<space_name>[-\w\./\s]+)/', 'view_space_index'),
)
空间/ views.py
def view_space_index(request, space_name):
"""
Show the index page for the requested space.
"""
place = get_object_or_404(Space, name=space_name)
return object_detail(request,
queryset = Space.objects.all(),
object_id = place.id,
template_name = 'spaces/index.html',
template_object_name = 'get_place')
答案 0 :(得分:30)
在您的space / urls.py文件中,您必须提供查看方法的完整路径:
urlpatterns = patterns('',
# Spaces
(r'^(?P<space_name>[-\w\./\s]+)/', 'spaces.views.view_space_index'),
)
或者像这样:
urlpatterns = patterns('spaces.views',
# Spaces
(r'^(?P<space_name>[-\w\./\s]+)/', 'view_space_index'),
)