Question

我有这三个数组：

const time = ["8n", "8n", "4n", "4n", "8n", "8n"];    
const note = [422, 303, 482, 419, 478, 467, 317, 343];    
const velocity = [0.57, 0.28, 0.35, 0.45, 0, 0.4, 0.53, 0.46, 0.48, 0.39];

如何将其转换为此内容，请注意匹配的索引：

const part = [
  { time: "8n", note: 422, velocity: 0.57 },
  { time: "8n", note: 303, velocity: 0.28 },
  { time: "4n", note: 482, velocity: 0.35 }
];

时间，音符和力度的起始数组长度将始终不同，因此部分长度应与前三个中的最小值相匹配。

非常感谢任何建议，谢谢。

Answer 1

你是说这个吗？

const time = ["8n", "8n", "4n", "4n", "8n", "8n"];
const note = [422, 303, 482, 419, 478, 467, 317, 343];
const velocity = [0.57, 0.28, 0.35, 0.45, 0, 0.4, 0.53, 0.46, 0.48, 0.39];

const merge = (timeArr, noteArr, velocityArr) => {
    const length = Math.min(time.length, note.length, velocity.length);
    const ret = [];

    for (let i = 0; i < length; i++) {
        ret.push({
            time: timeArr[i],
            note: noteArr[i],
            velocity: velocityArr[i]
        });
    }

    return ret;
};

console.log(merge(time, note, velocity));

Answer 2

像这样：

addEventListener('load', function(){
const time = ["8n", "8n", "4n", "4n", "8n", "8n"];    
const note = [422, 303, 482, 419, 478, 467, 317, 343];    
const velocity = [0.57, 0.28, 0.35, 0.45, 0, 0.4, 0.53, 0.46, 0.48, 0.39];
for(var i=0,part=[],l=time.length; i<l; i++){
  part.push({time:time[i], note:note[i], velocity:velocity[i]});
}
console.log(part);
});

Answer 3

您可以映射数组的所需部分。

＆＃13;

const time = ["8n", "8n", "4n", "4n", "8n", "8n"];
const note = [422, 303, 482, 419, 478, 467, 317, 343];
const velocity = [0.57, 0.28, 0.35, 0.45, 0, 0.4, 0.53, 0.46, 0.48, 0.39];

const merge = (timeArr, noteArr, velocityArr) => timeArr
    .slice(0, Math.min(time.length, note.length, velocity.length))
    .map((time, i) => ({
        time,
        note: noteArr[i],
        velocity: velocityArr[i]
    }));

console.log(merge(time, note, velocity));

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

将多个数组推入有序的对象数组中

3 个答案: