Question

我有两个问题：

SELECT 
    b.ref,
    ts.id_baits,
    SUM(strftime('%s',ts.endtime) -strftime('%s',ts.initime)) AS t,COUNT(*) AS n 
FROM TimeSegments AS ts
INNER JOIN Baits AS b ON b.id = ts.Id_Baits
GROUP BY  ts.id_baits
ORDER BY b.ref


SELECT  b.ref,
    COUNT(CASE WHEN e.Status=1 THEN 1 END) AS Undefined,
    COUNT(CASE WHEN e.Status=1 THEN 1 END) AS GetClose,
    COUNT(CASE WHEN e.Status=2 THEN 1 END) AS Threat,
    COUNT(CASE WHEN e.Status=3 THEN 1 END) AS Attack,
    COUNT(CASE WHEN e.Status=4 THEN 1 END) AS Hooked,
    COUNT(CASE WHEN e.Status=5 THEN 1 END) AS Captured,
    COUNT(CASE WHEN e.Status=6 THEN 1 END) AS Tagged,
    COUNT (*) AS TOTAL
FROM CastingsEvents AS e
LEFT JOIN Trajectories AS tr ON tr.id = e.id_trajectories 
LEFT JOIN TimeSegments AS ts ON ts.id = tr.id_timesegments
LEFT JOIN Baits AS b  ON b.id = ts.Id_Baits
GROUP BY  ts.id_baits
ORDER BY b.ref

如图所示，两个表都按id_baits分组。

我想将结果合并到一个表中，有人知道该怎么做吗？

Answer 1

根据提议（JOIN two SELECT statement results），LEFT JOIN解决问题：

SELECT * FROM (
    SELECT
        b.ref AS bait,
        ts.id_baits,
        SUM(strftime('%s',ts.endtime) -strftime('%s',ts.initime)) AS t,
        COUNT(*) AS n 
    FROM TimeSegments as ts
    INNER JOIN Baits as b ON b.id = ts.id_baits
    GROUP BY  ts.id_baits
) BaitsUsage 
LEFT JOIN (
    SELECT  
        ts.id_baits,
        COUNT(CASE WHEN e.Status=1 THEN 1 END) AS Undefined,
        COUNT(CASE WHEN e.Status=1 THEN 1 END) AS GetClose,
        COUNT(CASE WHEN e.Status=2 THEN 1 END) AS Threat,
        COUNT(CASE WHEN e.Status=3 THEN 1 END) AS Attack,
        COUNT(CASE WHEN e.Status=4 THEN 1 END) AS Hooked,
        COUNT(CASE WHEN e.Status=5 THEN 1 END) AS Captured,
        COUNT(CASE WHEN e.Status=6 THEN 1 END) AS Tagged,
        COUNT (*) AS TOTAL
    FROM CastingsEvents AS e
    LEFT JOIN Trajectories AS tr ON tr.id = e.id_trajectories 
    LEFT JOIN TimeSegments AS ts ON ts.id = tr.id_timesegments
    LEFT JOIN Baits AS b  ON b.id = ts.Id_Baits
    GROUP BY ts.id_baits
) BaitsEvents
ON BaitsUsage.id_baits=BaitsEvents.id_baits
ORDER BY bait

合并两个带有计数和总和的表格到一个结果中

1 个答案: