如果状态栏不是iPhone X,则显示隐藏状态栏,如果是iPhone X则显示状态栏。
很可能这必须以编程方式完成,因为在plist中没有支持此功能的键(我找到的最接近的是UIStatusBarHidden
)
答案 0 :(得分:5)
方法1:
您必须将此值添加到plist:" 查看基于控制器的状态栏外观"并将其设置为" 否"。
之后在AppDelegate
var window: UIWindow?
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
window = UIWindow(frame: UIScreen.main.bounds)
if #available(iOS 11.0, *) {
if (window?.safeAreaInsets.top)! > CGFloat(0.0) || window?.safeAreaInsets != .zero {
print("iPhone X")
application.isStatusBarHidden = false
//or UIApplication.shared.isStatusBarHidden = true
}
else {
print("Not iPhone X")
application.isStatusBarHidden = true
}
}
return true
}
方法2: " 查看基于控制器的状态栏外观"并将其设置为" 是"。 默认情况下。
与iOS11 + setStatusBarHidden
&不推荐使用isStatusBarHidden
,
可以从iOS7 +获取prefersStatusBarHidden,我们可以在ViewController
上设置状态栏可见性设置as-
struct StatusBarInfo {
static var isToHiddenStatus = false
}
var window: UIWindow?
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
if #available(iOS 11.0, *) {
if (window?.safeAreaInsets.top)! > CGFloat(0.0) || window?.safeAreaInsets != .zero {
print("iPhone X")
StatusBarInfo.isToHiddenStatus = false
}
else {
StatusBarInfo.isToHiddenStatus = true
print("Not iPhone X")
}
}
return true
}
在ViewController.Swift中
override var prefersStatusBarHidden: Bool {
return StatusBarInfo.isToHiddenStatus
}
答案 1 :(得分:0)
在此处查找完整帖子: How to get device make and model on iOS?
这是获取模型类型的函数:
extension UIDevice {
var modelName: String {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
return identifier
}
}
然后进行验证
override var prefersStatusBarHidden: Bool {
return UIDevice.current.modelName == "iPhone X"
}