Question

我遇到了一些问题，希望有人遇到这个问题并知道发生了什么。

我正在调用我们的WebAPI来获取$resource

的数据

（angularJS控制器代码）

 Controller.service.common.GetData.get({pubPolyData: objData}, function 
 (Response) {
                // success 
               Do stuff...

            }

（AngularJS服务）

GetData: $resource(myURL, {}),

通过类型为string的APIController（这是一个c＃可继承对象）。

我正在使用System.Net.WebClient();来调用response = client.DownloadString(theURI);，其中response是返回给AngularJS的内容。

这是在ApiController中返回的内容

{"ObjectName":[{"ID":"123456","FormalName":"LastName, FirstName","SearchName":null,"Number":"xx-123-456789","OfficeName":"Some Office INC","Code":"987654","CompanyCode":"852","StateAbbr":"MN"}]}

...但是你可以看到Controller.service.common.GetTheData.get({sendData: objData}, function (myResponse)调用myResponse的回复实际上是正确的数据，但是每个字符的数组都是分开的

Response       [object (Resource)]
   _proto_     [object (Resource)]
   $promise    [object (Promise)]
   $resolved   true
   [0]         "{"
   [1]         "\"
   [2]         "O"
   [3]         "b"
   [4]         "j"
   [5]         "e"
   [0]         "c"
   [1]         "t"
   [2]         "N"
   [3]         "a"
   [4]         "m"
   [5]         "e"
   [0]         ":"
   [1]         "["
   [2]         "{"
   [3]         "I"
   [4]         "D"
   [5]         ":"

...等

......我在这里错过了什么？

Answer 1

因此，实际问题是在HttpResponseMessage（本地控制器）类型的控制器内部获取HttpResponseMessage（来自远程WebAPI）并尝试将其传递回$ resource ... no bueno！

我实际做的是将Local控制器更改为SimpleResponse ...＆＃34; T＆＃34;是你想要填充的模型。是的，不幸的是，如果您因为某种原因需要在此处调用您的遥控器，则必须在本地控制器上复制模型。

有了这个，我反序列化了Object并将SimpleResponse返回到$ resource，一切都很开心!!

public class MyControllerController : ApiController {
    public SimpleResponse<DataModel> GET(string _inData) {            
        DataModel data = new DataModel();


            try {
                System.Net.WebClient client = new System.Net.WebClient();

                String Domain = CallToGetValueFromWebConfig("WEBAPIURL", "value");
                String theURI = String.Format("{0}api/ApIControllerName?_inData={1}", Domain, _inData);


                client.BaseAddress = theURI;
                client.UseDefaultCredentials = true;

                var json = client.DownloadString(theURI);

                data = JsonConvert.DeserializeObject<DataModel>(json, new JsonSerializerSettings() {
                    ContractResolver = new CamelCasePropertyNamesContractResolver()
                });



            } catch (Exception ex) {
                EventLogging.AddExceptionEvent(EventLogging.EventID.WebApiDataGet, "Some error text", ex);
            }

        return new SimpleResponse<DataModel> { Data = data}; 
    }
}
}

Answer 2

您可以使用Newtonsoft库

string json = "{\"ObjectName\":[{\"ID\":\"123456\",\"FormalName\":\"LastName, FirstName\",\"SearchName\":null,\"Number\":\"xx-123-456789\",\"OfficeName\":\"Some Office INC\",\"Code\":\"987654\",\"CompanyCode\":\"852\",\"StateAbbr\":\"MN\"}]}";
var response = Newtonsoft.Json.Linq.JToken.Parse(json)["ObjectName"];

这将返回

[
  {
    "ID": "123456",
    "FormalName": "LastName, FirstName",
    "SearchName": null,
    "Number": "xx-123-456789",
    "OfficeName": "Some Office INC",
    "Code": "987654",
    "CompanyCode": "852",
    "StateAbbr": "MN"
  }
]

JSON数据读取为单个字符数组

2 个答案: