Question

这是一个来自python初学者的简单问题：

我有一个包含子列表的列表：[[1,2,3]，['a'，'b'，'c']]

我想要[1,2,3]，['a'，'b'，'c']

我试过了：

M = [[1,2,3],['a','b','c']]
for item in M:
    print(item)

[1,2,3]

['a','b','c']

但我不想使用print，我需要将结果[1,2,3]，['a'，'b'，'c']嵌套到另一个循环中。

我尝试在网站上搜索类似的问题，但似乎无法找到我可以遵循的答案。你们能帮助我吗？谢谢！

Answer 1

Noticing your comment I have adjusted my answer with my attempt to deliver what you wanted. There are two options, option 1 with the dictionary will work with varying lengths of sublists

from collections import defaultdict

M = [[1,2,3],['a','b','c']]
d = defaultdict(list)
for sublist in M:
    for i,e in enumerate(sublist):
        d[i].append(e)
d = ["".join(str(e) for e in d[i]) for i in range(len(d))]
print (d)

#bonus alternative solution using zip()
d2 = ["".join(str(e) for e in tuple_) for tuple_ in zip(*M)]
print (d2)

Both print:

['1a', '2b', '3c']

将列表拆分为子列表python

1 个答案: