Question

请问如何使用post_export信号更新以下导出的公司模型。我不想导出之前未导出的项目。所以最好的方法是使用信号。

但是，如果我在下面代码末尾的信号中打印模型，我会得到一个类型类，例如<class 'app.models.Company'>

我知道通过保存模型我做错了但却找不到我的方式。

也许我不理解找到here的django-import-export库的文档。

models.py

class Company(models.Model):
    class Meta:
        verbose_name_plural = "Companies"

    company_name = models.CharField(max_length=254, blank=True)
    website = models.URLField(max_length=254, unique=True)
    address = models.CharField(max_length=254, blank=True, null=True)
    imported = models.BooleanField(default=False)
    exported = models.BooleanField(default=False)
    user = models.ForeignKey(User)

    def __str__(self):
        if self.company_name:
            return self.company_name
        return self.domain

admin.py

from django.dispatch import receiver 
from import_export.signals import post_import, post_export

class CompanyResource(resources.ModelResource):
    class Meta:
        model = Company
        fields = ('website', 'user', 'country', 'source', 'industry')

@admin.register(Company)
class CompanyAmin(ImportExportModelAdmin):
    resource_class = CompanyResource
    list_display = ('domain', 'website', 'exported', 'added_on')
    list_filter = ('user', 'country', 'imported', 'exported', 'added_on')


@receiver(post_export, dispatch_uid='ss1')
def _post_export(model, **kwargs):
    print(model) 
    model.exported = True
    model.save() # This line when included raises Error: "save() missing 1 required positional argument: 'self'" so code breaks here

Answer 1

https://docs.djangoproject.com/en/1.11/topics/signals/#connecting-receiver-functions

请注意，该函数采用sender参数和通配符关键字参数（** kwargs）;所有信号处理人员必须采取这些参数。

@receiver(post_export, dispatch_uid='ss1')
def _post_export(sender, model, **kwargs):
    model.exported = True
    model.save()

更新： django-import-export不会在信号

中发送导出的查询集

所以你可以在ModelAdmin中覆盖export_action

@admin.register(Company)
class CompanyAmin(ImportExportModelAdmin):
    resource_class = CompanyResource
    list_display = ('domain', 'website', 'exported', 'added_on')
    list_filter = ('user', 'country', 'imported', 'exported', 'added_on')

    def export_action(self, request, *args, **kwargs):
        response = super().export_action(request, *args, **kwargs)
        qs = self.get_export_queryset(request)
        qs.update(exported=True)
        return response

Answer 2

АрсенийКраснов解决方案有问题，在导出模型之前不更新模型。

要导出之后，必须在resources.ModelResource

中添加以下函数

angular.module('app')
.factory('httpInterceptor', ["$window", "$q", "$rootScope", "$injector", function ($window, $q, $rootScope, $injector) {
    return {
        request: function (config) {
            // Read the value from the $rootScope. If it's true, cancel all the subsequent requests
            var redirected = $rootScope.app.redirected;

            console.log("request: redirected: " + redirected); // The value is always 'undefined' here

            var canceller = $q.defer();
            if (redirected) {
                // Canceling request
                canceller.resolve();
            }
            return config;
        },
        responseError: function (response) {
            var statusCode = response.status;
            var newLocation = response.headers('location');
            if (statusCode === 420 && newLocation) { // Status code is 420. Redirect and set a flag in the $rootScope
                $rootScope.app.redirected = true;
                $window.location.href = newLocation;
            }
            return response || $q.when(response);
        }
    }
}])
.config(['$httpProvider', function($httpProvider) {
    $httpProvider.interceptors.push('httpInterceptor');
}]);

django-import-export：获取post_export来更新模型

2 个答案: