Question

希望我能正确解释一下。

我的代码

$eng[] = "All";
$eng[] = "engine_Sigma";
$eng[] = "engine_K-Series";
$eng[] = "engine_Duratec";
$eng[] = "engine_Suzuki";
$eng[] = "engine_Vauxhall";
$eng[] = "engine_Crossflow";

// query your db
$itemsq = mysqli_query($con,"SELECT * FROM `crm`.`workshop-items` LIMIT 0,100");
$items = mysqli_fetch_assoc($itemsq);
// do/while? should prob just use a while loop
do {
    $enginetype = explode(":", $items['engineid']);

    foreach ($enginetype as $key) {
        echo "$items[wsiid] - $items[code] - $items[incvat] - $eng[$key] <br>
";
    }

} while ($items = mysqli_fetch_assoc($itemsq));

然而，在DB中，engineid以1：3：6存储，或者甚至是1：2：3：4：5：6现在我想要做的是，如果有多个值，他们分手了，而不仅仅是回显第一个项目，然后再次回显下一个id的数据（像这个WSIID - CODE INCVAT engine_K-Series）等等我想做显示（WSIID - CODE - INCVAT - engine_Sigma engine_K-Series）如果$ eng是1＆amp; 3（1：3）

希望你能明白我的意思

谢谢你们

Answer 1

您应该回显foreach循环之外的数据的第一部分，并仅回显foreach内的引擎类型：

<?php
$eng[] = "All";
$eng[] = "engine_Sigma";
$eng[] = "engine_K-Series";
$eng[] = "engine_Duratec";
$eng[] = "engine_Suzuki";
$eng[] = "engine_Vauxhall";
$eng[] = "engine_Crossflow";

// query your db
$itemsq = mysqli_query($con,"SELECT * FROM `crm`.`workshop-items` LIMIT 0,100");
//$items = mysqli_fetch_assoc($itemsq); # you should delete this, see my explanation below
// do/while? should prob just use a while loop
do {
    $enginetype = explode(":", $items['engineid']);

    echo "$items[wsiid] - $items[code] - $items[incvat] - ";
    foreach ($enginetype as $key) {
       echo "$eng[$key] ";
    }
    echo "<br />";

} while ($items = mysqli_fetch_assoc($itemsq));

您应该删除第一次执行$items = mysqli_fetch_assoc($itemsq);，否则您的do...while循环将从第二次迭代开始。

从数组中获取多个值

1 个答案: