Question

我有2个表可供我使用，一个是带有start_date和end_date的main_table，另一个是holiday_table，其中标记了所有客户端假期以及周末。

我需要计算从start_date到end_date的所有工作日，从而消除该特定时间内holiday_table中发生的所有假期。

main_table（start_date日期，end_date日期）和holiday_table（假日日期）我有一段代码可以很容易地分开holiday_table中列出的所有假期，前提是start_date和end_date的值是硬编码的。代码：选择（to_date（'10 / 10/2017'，'mm / dd / yyyy'） - to_date（'10 / 01/2017'，'mm / dd / yyyy'）） - （从holiday_2016 t中选择计数（*）其中t.holidays＆gt; to_date（'10 / 01/2017'，

来自双重

'mm / dd / yyyy'）和t.holidays＆lt; = to_date（'10 / 10/2017'，'mm / dd / yyyy'））

但这不是我想要的，因为我有一个表，其中start_date和end_date有不同的值，因此，这些值不能被硬编码。

i/p tables : 
1. main_table
start_date  end_date
--------------------
10/01/2017  10/10/2017 
10/05/2017  10/20/2017
09/29/2017  10/05/2017

holiday_table
holidays
------------
10/01/2017 --Sunday 
10/02/2017 --Gandhi Jayanti 
10/07/2017 --Saturday 
10/08/2017 --Sunday 
10/14/2017 --Saturday 
10/15/2017 --Sunday 
10/19/2017 --Diwali

o/p table should be like :
start_date  end_date    bus_days
------------------------------------------
10/01/2017  10/10/2017    06 
10/05/2017  10/20/2017    10
09/29/2017  10/05/2017    04

++如果这样做，我需要在start_date和end_date中添加过滤器：

具有start_date＆lt;的请求'10 / 01/2017'和start_date＆gt; '10 / 20/2017'将被淘汰
具有end_date＆lt;的请求'10 / 01/2017'和start_date＆gt; '10 / 20/2017'也将被淘汰

Answer 1

这种方法过去对我来说有类似的需求

select
      t.START_DATE
    , t.END_DATE

    ,  trunc(to_number(t.END_DATE - t.START_DATE)) + 1
     - trunc(to_number(t.END_DATE - t.START_DATE) / 7) * 2
     - (CASE WHEN to_char(t.START_DATE,'day') = 'sunday' THEN 1 ELSE 0 END)
     - (CASE WHEN to_char(t.END_DATE,'day') = 'saturday' THEN 1 ELSE 0 END)
     weekdays

    ,  trunc(to_number(t.END_DATE - t.START_DATE)) + 1
     - trunc(to_number(t.END_DATE - t.START_DATE) / 7) * 2
     - (select count(*) from holiday_table 
        where holidays between t.START_DATE and t.END_DATE)
     businessdays_A

    ,  trunc(to_number(t.END_DATE - t.START_DATE)) + 1
     - trunc(to_number(t.END_DATE - t.START_DATE) / 7) * 2
     - (CASE WHEN to_char(t.START_DATE,'day') = 'sunday' THEN 1 ELSE 0 END)
     - (CASE WHEN to_char(t.END_DATE,'day') = 'saturday' THEN 1 ELSE 0 END)
     - (select count(*) from holiday_table 
        where holidays between t.START_DATE and t.END_DATE)
     businessdays_B

from main_table T

编辑现在我看到了一些示例数据我不确定您是否需要删除周末。看来您可能会在假期表中明确存储非工作日，因此您可能只需要这样：

    ,  trunc(to_number(t.END_DATE - t.START_DATE)) + 1
     - (select count(*) from holiday_table 
        where holidays between t.START_DATE and t.END_DATE)
     businessdays_C

SQL Fiddle

CREATE TABLE MAIN_TABLE
    (START_DATE DATE, END_DATE DATE)
;

INSERT ALL 
    INTO main_table (START_DATE, END_DATE)
         VALUES (TO_DATE('01-Oct-2017','dd-mon-yyyy'), TO_DATE('10-Oct-2017','dd-mon-yyyy'))
    INTO main_table (START_DATE, END_DATE)
         VALUES (TO_DATE('05-Oct-2017','dd-mon-yyyy'), TO_DATE('20-Oct-2017','dd-mon-yyyy'))
    INTO main_table (START_DATE, END_DATE)
         VALUES (TO_DATE('29-Sep-2017','dd-mon-yyyy'), TO_DATE('05-Oct-2017','dd-mon-yyyy'))
SELECT * FROM dual
;

CREATE TABLE HOLIDAY_TABLE
    (HOLIDAYS DATE, NAME varchar2(14))
;

INSERT ALL 
    INTO holiday_table (HOLIDAYS, NAME)
         VALUES (TO_DATE('01-Oct-2017','dd-mon-yyyy'), 'Sunday')
    INTO holiday_table (HOLIDAYS, NAME)
         VALUES (TO_DATE('02-Oct-2017','dd-mon-yyyy'), 'Gandhi Jayanti')
    INTO holiday_table (HOLIDAYS, NAME)
         VALUES (TO_DATE('07-Oct-2017','dd-mon-yyyy'), 'Saturday')
    INTO holiday_table (HOLIDAYS, NAME)
         VALUES (TO_DATE('08-Oct-2017','dd-mon-yyyy'), 'Sunday')
    INTO holiday_table (HOLIDAYS, NAME)
         VALUES (TO_DATE('14-Oct-2017','dd-mon-yyyy'), 'Saturday')
    INTO holiday_table (HOLIDAYS, NAME)
         VALUES (TO_DATE('15-Oct-2017','dd-mon-yyyy'), 'Sunday')
    INTO holiday_table (HOLIDAYS, NAME)
         VALUES (TO_DATE('19-Oct-2017','dd-mon-yyyy'), 'Diwali')
SELECT * FROM dual
;

查询1 ：

select
      t.START_DATE
    , t.END_DATE

    ,  trunc(to_number(t.END_DATE - t.START_DATE)) + 1
     - trunc(to_number(t.END_DATE - t.START_DATE) / 7) * 2
     - (CASE WHEN to_char(t.START_DATE,'day') = 'sunday' THEN 1 ELSE 0 END)
     - (CASE WHEN to_char(t.END_DATE,'day') = 'saturday' THEN 1 ELSE 0 END)
     weekdays

    ,  trunc(to_number(t.END_DATE - t.START_DATE)) + 1
     - trunc(to_number(t.END_DATE - t.START_DATE) / 7) * 2
     - (select count(*) from holiday_table 
        where holidays between t.START_DATE and t.END_DATE)
     businessdays_A

    ,  trunc(to_number(t.END_DATE - t.START_DATE)) + 1
     - trunc(to_number(t.END_DATE - t.START_DATE) / 7) * 2
     - (CASE WHEN to_char(t.START_DATE,'day') = 'sunday' THEN 1 ELSE 0 END)
     - (CASE WHEN to_char(t.END_DATE,'day') = 'saturday' THEN 1 ELSE 0 END)
     - (select count(*) from holiday_table 
        where holidays between t.START_DATE and t.END_DATE)
     businessdays_B

        ,  trunc(to_number(t.END_DATE - t.START_DATE)) + 1
         - (select count(*) from holiday_table 
            where holidays between t.START_DATE and t.END_DATE)
         businessdays_C

from main_table T

<强> Results ：

|           START_DATE |             END_DATE | WEEKDAYS | BUSINESSDAYS_A | BUSINESSDAYS_B | BUSINESSDAYS_C |
|----------------------|----------------------|----------|----------------|----------------|----------------|
| 2017-10-01T00:00:00Z | 2017-10-10T00:00:00Z |        8 |              4 |              4 |              6 |
| 2017-10-05T00:00:00Z | 2017-10-20T00:00:00Z |       12 |              7 |              7 |             11 |
| 2017-09-29T00:00:00Z | 2017-10-05T00:00:00Z |        7 |              5 |              5 |              5 |

如何计算Oracle中的工作日

1 个答案: