Question

我已经阅读了几个关于计算连续行的类似问题，但没有一个给我一个明确的答案。我希望有人可以帮我解决一下我的问题。我有以下表格数据：

ID       TEST_VALUES
 1       A
 2       B
 3       C
 4       C
 5       C
 6       C
 7       A
 8       D
 9       D
 10      D
 11      B
 12      C
 13      C
 14      C
 15      C

现在我想在ID范围内找到具有相同值的三个连续行是1到10，例如当ID范围是1到10时，有'C'连续出现超过三次。（注意：这个问题与ID无关，列ID只是我查询的条件，例如ID＆gt; 1和ID＆lt; 10）

Answer 1

SELECT
    GROUP_CONCAT(`TEST_VALUES` ORDER BY `id` ASC) AS g
FROM
    `tbl`
WHERE
    `ID` >=1 AND `ID` <= 10
HAVING
    g LIKE '%C,C,C,C%'

按GROUP_CONCAT()订购id可确保结果是连续的。 HAVING子句仅提取包含至少四个C序列实例的行。

Answer 2

你可以试试这个，

SELECT TEST_VALUES, MAX(cnt) AS maxCount
FROM (
  SELECT TEST_VALUES, ID, COUNT(grp) AS cnt
  FROM (
    SELECT ID, TEST_VALUES, rn - rnByVal AS grp
    FROM (
      SELECT ID, TEST_VALUES,
           @rn := @rn + 1 AS rn,
           @rnByVal := IF (@val = TEST_VALUES,
                          IF (@val := TEST_VALUES, @rnByVal + 1, @rnByVal + 1),
                          IF (@val := TEST_VALUES, 1, 1)) AS rnByVal
      FROM mytable
      CROSS JOIN (SELECT @rn := 0, @rnByVal := 0, @val := '') AS vars
      ORDER BY ID) AS t 
    ) AS s
  GROUP BY TEST_VALUES, grp ) AS u
GROUP BY TEST_VALUES

对于具有相同值（大于1）的连续行的返回最大计数。

Answer 3

我也想到了一个解决方案，希望能帮助别人

SELECT 
TEST_VALUES 
FROM(
    SELECT
    m.TEST_VALUES AS TEST_VALUES,
    IF(@b = m.TEST_VALUES, @a := @a +1, @a := 0) AS countNUM,
    @b := m.TEST_VALUES
    FROM tableName m
    JOIN (
      SELECT 
      @a := 0
    ) AS t
) AS TEMP
WHERE countNUM >= 2
GROUP BY TEST_VALUES

Answer 4

令人费解但经过测试和运作：

    SELECT t1.ID AS t1_id, t1.TEST_VALUES AS t1_values,
(SELECT ID FROM test WHERE test.ID > t1.ID LIMIT 1 ) AS t2_id, (SELECT TEST_VALUES FROM test WHERE test.ID > t1.ID LIMIT 1 ) AS t2_values,
(SELECT ID FROM test WHERE test.ID > (SELECT ID FROM test WHERE test.ID > t1.ID LIMIT 1 ) LIMIT 1 ) AS t3_id, (SELECT TEST_VALUES FROM test WHERE test.ID > (SELECT ID FROM test WHERE test.ID > t1.ID LIMIT 1 ) LIMIT 1 ) AS t3_values,
(SELECT ID FROM test WHERE test.ID > (SELECT ID FROM test WHERE test.ID > (SELECT ID FROM test WHERE test.ID > t1.ID LIMIT 1 ) LIMIT 1 ) LIMIT 1 ) AS t4_id, (SELECT TEST_VALUES FROM test WHERE test.ID > (SELECT ID FROM test WHERE test.ID > (SELECT ID FROM test WHERE test.ID > t1.ID LIMIT 1 ) LIMIT 1 ) LIMIT 1 ) AS t4_values
FROM test AS t1
HAVING (
    ID BETWEEN 1 AND 10 AND t2_id BETWEEN 1 AND 10 AND t3_id BETWEEN 1 AND 10 AND t4_id BETWEEN 1 AND 10
        AND
t1_values = t2_values AND t2_values = t3_values AND t3_values = t4_values
)

给出了这些结果：

+-------+-----------+-------+-----------+-------+-----------+-------+-----------+
| t1_id | t1_values | t2_id | t2_values | t3_id | t3_values | t4_id | t4_values |
+-------+-----------+-------+-----------+-------+-----------+-------+-----------+
|     3 | C         |     4 | C         |     5 | C         |     6 | C         |
+-------+-----------+-------+-----------+-------+-----------+-------+-----------+
1 row in set (0.03 sec)

mysql找到三个具有相同值的连续行

4 个答案: