我对javascript不好。我正在使用基于本教程的facebox登录表单:
http://freecss.info/css-tutorials/jquery-ajax-contact-form-in-facebox/
错误处理工作正常。问题=如果没有错误,我的标题(“location:index.php”)会加载到facebox中。
如何关闭面板并重新加载页面?
答案 0 :(得分:1)
您需要更改响应的行为,以便控制何时显示成功时的错误以及何时重定向,请检查以下更改:
sendemail.php:
<?php
/************************
* Variables you can change
*************************/
$mailto = "mikkaclarke@hotmail.com";
$cc = "";
$bcc = "";
$subject = "Email subject";
$vname = "BrightCherry enquiry";
/************************
* do not modify anything below unless you know PHP/HTML/XHTML
*************************/
$email = $_POST['email'];
$resp['error'] = FALSE; // by default there are no errors
function validateEmail($email)
{
if(eregi('^[a-zA-Z0-9._-]+@[a-zA-Z0-9-]+\.[a-zA-Z]{2,4}(\.[a-zA-Z]{2,3})?(\.[a-zA-Z]{2,3})?$', $email))
return true;
else
return false;
}
if((strlen($_POST['name']) < 1 ) || (strlen($email) < 1 ) || (strlen($_POST['message']) < 1 ) || validateEmail($email) == FALSE){
$resp['error'] = TRUE;
$emailerror .= 'Error:';
if(strlen($_POST['name']) < 1 ){
$emailerror .= '<li>Enter name</li>';
}
if(strlen($email) < 1 ){
$emailerror .= '<li>Enter email</li>';
}
if(validateEmail($email) == FALSE) {
$emailerror .= '<li>Enter valid email</li>';
}
if(strlen($_POST['message']) < 1 ){
$emailerror .= '<li>Enter message</li>';
}
$err = "<div id='emailerror'><ul>$emailerror</ul></div>";
$resp['error_msg'] = $err;
} else {
$emailerror .= "<span>Your email has been sent successfully!</span>";
// NOW SEND THE ENQUIRY
$timestamp = date("F j, Y, g:ia");
$messageproper ="\n\n" .
"Name: " .
ucwords($_POST['name']) .
"\n" .
"Email: " .
ucwords($email) .
"\n" .
"Comments: " .
$_POST['message'] .
"\n" .
"\n\n" ;
$messageproper = trim(stripslashes($messageproper));
mail($mailto, $subject, $messageproper, "From: \"$vname\" <".$_POST['e_mail'].">\nReply-To: \"".ucwords($_POST['first_name'])."\" <".$_POST['e_mail'].">\nX-Mailer: PHP/" . phpversion() );
}
echo json_encode($resp);
?>
你的联系人和索引中的ajaxForm
(我不知道你为什么需要它):
$('#submitform').ajaxForm({
dataType: 'json',
success: function(resp) {
if(resp.error)
$('#error').html(resp.error_msg).fadeIn('slow');
else
window.location = 'index.php';
}
});
我所做的是以下内容:
json