我的NodeJS应用程序使用request-promise-native。
import request from 'request-promise-native'
const https = require('https')
const myRequest = request.defaults({
baseUrl: 'myBaseUrl',
agent: new https.Agent({ keepAlive: true })
})
async function findResults() {
const myResponse = await myRequest.get({
uri: '/myUri'
})
return myResponse
}
我正试图模仿'获得'上述单元测试请求。但它仍然会进行实际调用并获得结果,而不是通过我的模拟对象调用。
我使用Sinon尝试了不同的变体:
import test from 'ava'
import sinon from 'sinon'
import Bluebird from 'bluebird'
import request from 'request-promise-native'
import { findResults } from '../services/results'
test.only(async t => {
let response = JSON.stringify({
statusCode: 504
})
sinon.stub(request, 'get').returns(Bluebird.resolve(response))
const returnValue = await findResults()
console.log('return: ', returnValue)
t.is (1, 1)
})
使用Mockery(根据文档https://www.npmjs.com/package/request-promise)
import mockery from 'mockery'
import { findResults } from '../services/results'
test.before(async t => {
mockery.enable({
warnOnReplace: false,
warnOnUnregistered: false,
useCleanCache: true
})
mockery.registerMock('request-promise-native', function () {
// var response = fs.readFileSync(__dirname + '/data/' + filename, 'utf8');
let response = JSON.stringify({
statusCode: 9
})
return Bluebird.resolve(response.trim());
})
})
test.after(async t => {
mockery.disable()
mockery.deregisterAll()
// done()
})
test.only(async t => {
const returnValue = await findResults()
console.log('return: ', returnValue)
t.is(1, 1)
})
我也试过了proxyquire和sinon的假服务器的变种。但我无法让他们工作。
有什么建议吗?
答案 0 :(得分:1)
通常,如果在导入的包上使用sinon spy,您可以像sinon.spy(request.prototype, 'get')
那样创建存根。这在这里不起作用,大概是因为请求没有定义原型上的方法。解决这个问题的一种方法是在实例上创建存根(如果你可以调用它)。示例如下:
const request = require( 'request-promise-native')
const https = require('https')
const {expect} = require('chai')
require('mocha')
const sinon = require('sinon')
const Bluebird = require( 'bluebird')
const myRequest = request.defaults({
baseUrl: 'myBaseUrl',
agent: new https.Agent({ keepAlive: true })
})
async function findResults() {
const myResponse = await myRequest.get({
uri: '/myUri'
})
return myResponse
}
async function mainTest() {
let response = JSON.stringify({
statusCode: 504
})
sinon.stub(myRequest, 'get').callsFake((params) => Bluebird.resolve(response))
const returnValue = await findResults()
console.log('return: ', returnValue)
}
mainTest()
答案 1 :(得分:0)
我使用了proxyquire。以下是我用来模拟请求承诺的一些代码:
const proxyquire = require('proxyquire');
before(function (done) {
rpMock = function () {
var response = generateFakeResponse();
return Bluebird.resolve(response.trim());
};
done();
});
// actual test:
it('tests my function', function () {
let MyModule = proxyquire('./MyModule',{'request-promise':rpMock});
let myModuleObj = new MyModule();
}