Question

我正在使用此查询按ASC顺序获取数据 从list_tbl中选择*其中cat_id =％d按名称排序ASC

现在我的表视图显示了基于ASC顺序的数据然后我用它来获取右侧A到Z的字母

- (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)help
{
    return [[[UILocalizedIndexedCollation currentCollation] sectionTitles] objectAtIndex:help];
}
-(NSArray *)sectionIndexTitlesForTableView:(UITableView *)tableView
{
    return [[UILocalizedIndexedCollation currentCollation] sectionIndexTitles];
}



- (NSInteger)tableView:(UITableView *)tableView sectionForSectionIndexTitle:(NSString *)title atIndex:(NSInteger)index
{
    return [[UILocalizedIndexedCollation currentCollation] sectionForSectionIndexTitleAtIndex:index];
}

现在我的问题是如何基于章节标题划分数据，就像所有A内容转到A然后B转到Z，当用户点击右侧的任何字母时，它应该转到该部分

//更新///////////////

-(void)setUpRecordsForIndexing
{

        for (NSString * recordName in appDelegate.catLists)//where app.catList contains all the value
        {
           NSString *firstLetter = ([recordName length] ==0)?miscKey:[[recordName substringToIndex:1]uppercaseString];
            /*if(![firstLetter beginsWithCharacterInSet:[NSCharacterSet letterCharacterSet]] || [recordName isEqualToString:@""] || recordName == nil )
                firstLetter = miscKey ;
        */  
            NSMutableArray *indexArray = [IndexedRecords objectForKey:firstLetter];
            if (indexArray == nil) 
            {
                indexArray = [[NSMutableArray alloc] init];
                [IndexedRecords setObject:indexArray forKey:firstLetter];
                [IndexLetters addObject:firstLetter];
                [indexArray release];
            }
            [indexArray addObject:record];// this is not workking

        //  NSLog(@" index array is %@",indexArray);
        }
    }

我的INDEXRECORD没有显示正确的值我现在可以基于ABCD划分该部分，但每个部分都有相同的内容，我做错了

Answer 1

例如：说RecordsArray包含你的所有记录，现在在表视图中数据源方法numberOfSectionsInTableView再调用一个方法来索引你所有的记录，如下所示

-(void)setUpRecordsForIndexing
{
    if(IndexedRecords)
    {
        [IndexedRecords release];
        IndexedRecords = nil;
    }

    if(IndexLetters)
    {
        [IndexLetters release];
        IndexLetters = nil;
    }

    IndexedRecords = [[NSMutableDictionary alloc] init];
    IndexLetters = [[NSMutableArray alloc] init];

    NSString *miscKey = @"#";
    for (NSString * recordName in RecordsArray)
    {
        NSString *firstLetter = ([recordName length] ==0)?miscKey:[[recordName substringToIndex:1]uppercaseString];
        if(![firstLetter beginsWithCharacterInSet:[NSCharacterSet letterCharacterSet]] || [recordName isEqualToString:@""] || recordName == nil )
            firstLetter = miscKey ;

        NSMutableArray *indexArray = [mIndexedRecords objectForKey:firstLetter];
        if (indexArray == nil) 
        {
            indexArray = [[NSMutableArray alloc] init];
            [IndexedRecords setObject:indexArray forKey:firstLetter];
            [IndexLetters addObject:firstLetter];
            [indexArray release];
        }
        [indexArray addObject:record];
    }
}

并在numberOfSectionsInTableView中返回IndexLetters的计数。我希望这能解决你的问题。

Answer 2

在索引记录时，请将您的记录保存在字典中，如IndexedRecords。这样，对于键“A”设置，记录数组以字母“A”开头。并填充表格视图

[[IndexedRecords objectForKey:[IndexLetters objectAtIndex:indexPath.section]]objectAtIndex:indexPath.row]

IndexLetters也是一个包含当前列表的索引字母的数组。

在iphone上的UItableview中对数据进行排序和显示

2 个答案: