Question

我有数组我想“优化”，而不是手动添加pg1-pg11，我想使用“for”。

如何使其成为核心？

$query = array(
    'e1' => $_POST['npole3-1'], 
    'e2' => $_POST['npole3-2'],
    'e3' => $_POST['npole3-3'],
    'e4' => $_POST['npole3-4'],
    'e5' => $_POST['npole3-5'],
    'e6' => $_POST['npole3-6'],
    'e7' => $_POST['npole3-7'],
    'e8' => $_POST['npole3-8'],
    'e9' => $_POST['npole3-9'],
    'e10' => $_POST['npole3-10'],
    'e11' => $_POST['npole3-11'],
    'e12' => $_POST['npole3-12'],
    'e13' => $_POST['npole3-13'],
    'e14' => $_POST['npole3-14'],
    'e15' => $_POST['npole3-15'],
    'e16' => $_POST['npole3-16'],
    'e17' => $_POST['npole3-17'],
    'e18' => $_POST['npole3-18'],   
    );

for ($i = 1; $i <= 11; $i++) {array_push($query, ('pg1' => $_POST['pgadd-' . i]))};

Answer 1

$query = array();

for ($i = 1; $i <= 11; $i++) {

      // if exists in post array then
      if(isset($_POST['pgadd-' . $i])){

          // then add to query array
          // array key will be like pg1, pg2, pg3 ...
          // array value will be from your post data pgadd-1. pgadd-2

          $query['pg'.$i] = $_POST['pgadd-' . $i];
      }
}

// to see what's there inside array
print_r($query);

php将multipe $ _POST参数添加到数组中

1 个答案: