Question

我正在使用tweepy的Streamlistener来收集Twitter数据，而我正在使用的代码会生成带有大量元数据的JSONL文件。现在我想将文件转换为CSV，我为此找到了一个代码。不幸的是我遇到了错误阅读：

raise JSONDecodeError("Extra data", s, end)
json.decoder.JSONDecodeError: Extra data: line 2 column 1 (char 7833)

我已阅读其他线程，我认为它与json.loads无法处理json文件中的多个数据部分有关（当然，我的json列表文件就是这种情况）。我如何在代码中绕过这个问题？或者我是否必须使用完全不同的方法来转换文件？（我正在使用python 3.6，我正在流式传输的推文主要是阿拉伯文）。

__author__ = 'seandolinar'
import json
import csv
import io

'''
creates a .csv file using a Twitter .json file
the fields have to be set manually
'''

data_json = io.open('stream_____.jsonl', mode='r', encoding='utf-8').read() #reads in the JSON file
data_python = json.loads(data_json)

csv_out = io.open('tweets_out_utf8.csv', mode='w', encoding='utf-8') #opens csv file


fields = u'created_at,text,screen_name,followers,friends,rt,fav' #field names
csv_out.write(fields)
csv_out.write(u'\n')

for line in data_python:

#writes a row and gets the fields from the json object
#screen_name and followers/friends are found on the second level hence two get methods
row = [line.get('created_at'),
       '"' + line.get('text').replace('"','""') + '"', #creates double quotes
       line.get('user').get('screen_name'),
       unicode(line.get('user').get('followers_count')),
       unicode(line.get('user').get('friends_count')),
       unicode(line.get('retweet_count')),
       unicode(line.get('favorite_count'))]

row_joined = u','.join(row)
csv_out.write(row_joined)
csv_out.write(u'\n')




csv_out.close()

Answer 1

如果数据文件由多行组成，每行都是一个json对象，则可以使用生成器一次解码一行。

def extract_json(fileobj):
    # Using "with" ensures that fileobj is closed when we finish reading it.
    with fileobj:
        for line in fileobj:
            yield json.loads(line)

您的代码的唯一更改是data_json文件未明确读取，data_python是调用extract_json而不是json.loads的结果。这是修改后的代码：

import json
import csv
import io

'''
creates a .csv file using a Twitter .json file
the fields have to be set manually
'''

def extract_json(fileobj):
    """
    Iterates over an open JSONL file and yields
    decoded lines.  Closes the file once it has been
    read completely.
    """
    with fileobj:
        for line in fileobj:
            yield json.loads(line)    


data_json = io.open('stream_____.jsonl', mode='r', encoding='utf-8') # Opens in the JSONL file
data_python = extract_json(data_json)

csv_out = io.open('tweets_out_utf8.csv', mode='w', encoding='utf-8') #opens csv file


fields = u'created_at,text,screen_name,followers,friends,rt,fav' #field names
csv_out.write(fields)
csv_out.write(u'\n')

for line in data_python:

    #writes a row and gets the fields from the json object
    #screen_name and followers/friends are found on the second level hence two get methods
    row = [line.get('created_at'),
           '"' + line.get('text').replace('"','""') + '"', #creates double quotes
           line.get('user').get('screen_name'),
           unicode(line.get('user').get('followers_count')),
           unicode(line.get('user').get('friends_count')),
           unicode(line.get('retweet_count')),
           unicode(line.get('favorite_count'))]

    row_joined = u','.join(row)
    csv_out.write(row_joined)
    csv_out.write(u'\n')

csv_out.close()

将JSONL文件转换为CSV - ＆＃34; JSONDecodeError：额外数据＆＃34;

1 个答案: