Question

以下是我的查询。 Access不喜欢它，给我错误Syntax error (missing operator) in query expression 'answer WHERE question = 1'.

希望你能看到我想要做的事情。请特别注意SELECT声明下的第3行，第4行和第5行。

INSERT INTO Table2 (respondent,1,2,3-1,3-2,3-3,4,5)
SELECT respondent,
answer WHERE question = 1,
answer WHERE question = 2,
answer WHERE answer = 'text 1' AND question = 3,
answer WHERE answer = 'text 2' AND question = 3,
answer WHERE answer = 'text 3' AND question = 3,
answer WHERE question = 4,
longanswer WHERE question 5 FROM Table1 GROUP BY respondent;

更新

我已经取得了一些进展，但我仍然无法以我真正想要的格式获取数据。我使用了几个Iif语句来获取我现在的语句，但GROUP BY根本没有按照我期望的方式工作。我还尝试了SELECT语句的变体（例如SELECT DISTINCT TOP 100 PERCENT和TRANSFORM），但我想我没有正确使用它们，因为我总是会遇到错误。以下是我现在的数据：

alt text

现在我需要做的就是将所有类似的respondent行粉碎在一起（即respondent行具有相同的数字），以便删除所有空的单元格。

Answer 1

编辑：我不确定这是否是您要找的

我认为你想要做的就是这个（你在SELECT部分中不能有WHERE）：

INSERT INTO Table2 (respondent,1,2,3-1,3-2,3-3,4,5)
SELECT respondent,
Iif(question = 1, answer, 0),
Iif(question = 2, answer, 0),
Iif(answer = 'text 1' AND question = 3, answer, 0),
Iif(answer = 'text 2' AND question = 3, answer, 0),
Iif(answer = 'text 3' AND question = 3, answer, 0),
Iif(question = 4, answer)
Iif(question 5 NOT IS NULL, longanswer)
FROM Table1 GROUP BY respondent;

我认为问题5会起作用但不完全确定，我认为这是正确的。

如果你喜欢这样，你应该可以用0替换0。

Answer 2

你“将所有类似的响应行粉碎在一起（即具有相同数字的响应行）所以删除所有空单元格的方式”很简单：你使用GROUP BY。

假设（您还没有给我们架构）源表的架构看起来像这样：

create table response
(
  respondent_id int          not null , -- PK.1 respondent
  question_id   int          not null , -- PK.2 question number
  answer        varchar(200)     null ,

  primary key clustered ( respondent_id , question_id ) ,

)

也就是说每个响应者最多只有一个特定问题的响应，然后你的select语句来获得所需的结果集看起来像这样（在Transact-SQL中 - Access SQL看起来会有所不同：< / p>

select respondent_id = t.respondent_id ,
       q1            = max( q1.answer  ) ,
       q2            = max( q2.answer  ) ,
       q3a           = max( q3a.answer ) ,
       q3b           = max( q3b.answer ) ,
       q3c           = max( q3c.answer ) ,
       q4            = max( q4.answer  ) ,
       q5            = max( q5.answer  )
from ( select distinct respondent_id from response ) t
left join response q1  on q1.respondent_id  = t.respondent_id and q1.question_id  = 1
left join response q2  on q2.respondent_id  = t.respondent_id and q2.question_id  = 2
left join response q3a on q3a.respondent_id = t.respondent_id and q3a.question_id = 3 and q3a.answer = 'q3a answer'
left join response q3b on q3b.respondent_id = t.respondent_id and q3b.question_id = 3 and q3b.answer = 'q3b answer'
left join response q3c on q3c.respondent_id = t.respondent_id and q3c.question_id = 3 and q3c.answer = 'q3c answer'
left join response q4  on q4.respondent_id  = t.respondent_id and q4.question_id  = 4
left join response q5  on q5.respondent_id  = t.respondent_id and q5.question_id  = 5
group by t.respondent_id

您也可以使用FROM子句中的单个表来执行此操作，因此：

select respondent_id = t.respondent_id ,
       q1            = max( case t.question_id when 1 then t.answer else null end ) ,
       q2            = max( case t.question_id when 2 then t.answer else null end ) ,
       q3a           = max( case when t.question_id = 3 and t.answer = 'q3a answer' then t.answer else null end ) ,
       q3b           = max( case when t.question_id = 3 and t.answer = 'q3b answer' then t.answer else null end ) ,
       q3c           = max( case when t.question_id = 3 and t.answer = 'q3c answer' then t.answer else null end ) ,
       q4            = max( case t.question_id when 4 then t.answer else null end ) ,
       q5            = max( case t.question_id when 5 then t.answer else null end )
from response t
group by t.respondent_id

Answer 3

终于把这一切都整理好了。我在正确的轨道上走了很长一段时间，但只是没有完全正确。删除一些不需要的列并执行一些重要的格式化后，我能够运行以下查询以生成我需要的结果。感谢您的所有建议。

TRANSFORM Max(Sheet1.[answer]) AS MaxOfanswer
SELECT Sheet1.[respondent], Max(Sheet1.[answer]) AS [Total Of answer]
FROM Sheet1
GROUP BY Sheet1.[respondent]
PIVOT Sheet1.[question];

从一个表访问SELECT查询到SELECT，然后INSERT到另一个表

3 个答案: