我试图解决这个问题,我如何在另一个班级的班级中使用公共方法。我收到此错误
Site_id, PRP_Fabric, Phase12 {count}, Phase 13 {count}
6, BORDB, 507, 507
6, BORDG, 507, 0
6, BORDG CHP2, 507, 507
6, BORDO, 507, 0
我有包含insert方法的主类用户,基本上这个方法将值插入数据库。
try:
import tkinter
from tkinter import ttk
except ImportError:
import Tkinter as tkinter
import ttk
class Mainpage:
def __init__(self, master):
self.master = master
self.frame = tkinter.Frame(self.master)
self.master.columnconfigure(0, weight=1)
self.master.columnconfigure(1, weight=3)
self.master.columnconfigure(2, weight=1)
self.master.columnconfigure(3, weight=1)
self.master.columnconfigure(4, weight=1)
self.searchfield = tkinter.Frame(self.master)
self.searchfield.grid(row=1, column=0, columnspan=4)
self.search_var = tkinter.StringVar()
self.search_var.trace("w", lambda name, index, mode: self.selected)
self.entry = tkinter.Entry(self.searchfield, textvariable=self.search_var, width=45)
self.entry.grid(row=0, column=0, padx=10, pady=3)
self.searchbtn = tkinter.Button(self.searchfield, text='Search', command=self.selected)
self.searchbtn.grid(row=0, column=1)
self.treeFrame = tkinter.Listbox(self.searchfield, width=45, height=150)
self.treeFrame.grid(row=1, column=0, padx=10, pady=3)
self.tree = ttk.Treeview( self.treeFrame, columns=('Status', 'Name', 'Date'))
self.tree.heading('#0', text='Status')
self.tree.heading('#1', text='Name')
self.tree.heading('#2', text='Date')
self.tree.heading('#3', text='Transact Code')
self.tree.column('#0', stretch=tkinter.YES)
self.tree.column('#1', stretch=tkinter.YES)
self.tree.column('#2', stretch=tkinter.YES)
self.tree.column('#3', stretch=tkinter.YES)
self.tree.grid(row=0, columnspan=4, sticky='nsew')
self.treeview = self.tree
self.i = 1
self.patient_list = [{"Name":"Harry Thuku", "Date":"07.09.2017"},
{"Name":"stella stl", "Date": "07.09.2017"},
{"Name":"geg be", "Date": "07.09.2017"},
{"Name":"Henry Reeta", "Date": "06.09.2017"},
{"Name":"Henry Reeta", "Date": "06.09.2017"}]
for p in self.patient_list:
self.tree.insert('', 'end', text="ID_"+str(self.i), values=
(p["Name"], p["Date"]), tags=p["Name"])
self.i = self.i + 1
self.search_item = self.entry.get()
for p in self.patient_list:
if p["Name"] == self.search_item:
self.selected(self.search_item)
self.frame.bind("<Button-3>", self.click)
self.frame.grid_location(0, 0)
def selected(self):
search_for = self.search_var.get()
iid_to_select = ()
if search_for != '':
all_tags = self.master.tk.call(str(self.tree), "tag", "names")
tags_to_select = tuple(filter(lambda tag: search_for.lower() in tag.lower(), all_tags))
for sorted_tag in tags_to_select:
iid_to_select += self.tree.tag_has(sorted_tag)
self.tree.selection_set(iid_to_select)
def click(self, event):
print("Clicked at: ", event.x, event.y)
self.master.withdraw()
self.toplevel = tkinter.Toplevel(self.master)
self.toplevel.geometry("480x480")
app = PatientPage(self.toplevel)
class PatientPage:
#.....
pass
root = tkinter.Tk()
root.title("Login")
root.geometry("480x480")
Mainpage(root)
root.mainloop()
这是我的config.php文件来实例化类,所以我可以使用它们
Fatal error: Uncaught Error: Using $this when not in object context
我还有其他课程消息,然后按照。在后续类中,我可以从用户类访问所有方法,在消息类中我尝试使用在用户类中的插入方法
<?php
class User{
protected $pdo;
public function __construct($pdo){
$this->pdo = $pdo;
}
public function insert($table, $fields){
//here we insert the values into database
}
}
?>
在下面的课程中我尝试使用sendNotification方法,请记住此方法在消息类中,并且它使用来自用户类的方法
<?php
session_start();
include 'database/connection.php';
include 'classes/user.php';
include 'classes/follow.php';
include 'classes/message.php';
global $pdo;
$userObj = new User($pdo);
$followObj = new Follow($pdo);
$messageObj = new Message($pdo);
?>
致命致命错误
<?php
class Message extends User{
public function __construct($pdo){
$this->pdo = $pdo;
}
public static function sendNotification($user_id, $followerID, $type){
//calling this method from user class
$this->insert('notifications', array('By' => $user_id, 'To' => $followerID, 'type' => $type));
}
}
?>
我该怎么办?
答案 0 :(得分:0)
您正尝试在此方法中使用静态方法访问$ this:
public static function sendNotification($user_id, $followerID, $type){
//calling this method from user class
$this->insert('notifications', array('By' => $user_id, 'To' => $followerID, 'type' => $type));
您可以将sendNotification设为非静态并创建Message实例,以便您能够访问User的公共成员
答案 1 :(得分:0)
使$this
成为非静态函数。删除$message = new Message($this->pdo);//pass database connection
$message->sendNotification();//pass the variables
关键字
当方法不依赖于已实例化的类时,请使用静态方法。因此无法使用apiVersion: extensions/v1beta1
kind: Deployment
metadata:
name: my-database
labels:
app: my-database
spec:
replicas: 1
strategy:
type: Recreate
template:
metadata:
labels:
app: my-database
spec:
containers:
- image: postgres:9.6.3
name: my-database
ports:
- containerPort: 5432
resources: {}
volumeMounts:
- mountPath: "/var/lib/postgresql/data:Z"
name: postgresdb-storage
restartPolicy: Always
volumes:
- name: postgresdb-storage
persistentVolumeClaim:
claimName: postgresdb-volume-claim
status: {}
的原因
在以下功能中,改为执行此操作
apiVersion: v1
kind: PersistentVolume
metadata:
name: postgresdb-volume
spec:
storageClassName: postgresdb-class
accessModes:
- ReadWriteMany
capacity:
storage: 100Gi
nfs:
server: <NFS_SERVER_IP_ADDRESS>
path: /var/nfs/data/my-database-data