Question

找到CreateViewStream，现在我想创建int

在内存中使用MemoryMappedViewAccessor

// Process A:
    static void Main(string[] args)
    {
        using (MemoryMappedFile mmf = MemoryMappedFile.CreateNew("testmap", 10000))
        {
        bool mutexCreated;
        Mutex mutex = new Mutex(true, "testmapmutex", out mutexCreated);
        using (MemoryMappedViewStream stream = mmf.CreateViewStream())
        {
            BinaryWriter writer = new BinaryWriter(stream);
            writer.Write(1);
        }
        mutex.ReleaseMutex();

        // Read Int 
        MemoryMappedViewAccessor accessor = mmf.CreateViewAccessor();
        // For Process B Read
        accessor.Write(499, 41);
        // For Process B Read
        accessor.Write(500, 42);
        // For Process C Read
        accessor.Write(501, 43);
        accessor.Dispose();

        Console.WriteLine("Start Process B and press ENTER to continue.");
        Console.ReadLine();

        Console.WriteLine("Start Process C and press ENTER to continue.");
        Console.ReadLine();

        mutex.WaitOne();
        using (MemoryMappedViewStream stream = mmf.CreateViewStream())
        {
            BinaryReader reader = new BinaryReader(stream);
            MemoryMappedViewAccessor access = mmf.CreateViewAccessor();
            Console.WriteLine("Process A says: {0} ", reader.ReadBoolean());
            Console.WriteLine("Process B says: {0} ", reader.ReadBoolean());
            Console.WriteLine("Process C says: {0} ", reader.ReadBoolean());

            Console.WriteLine("Process A Int:{0}", access.ReadInt32(499));
            Console.WriteLine("Process B Int:{0}", access.ReadInt32(500));
            Console.WriteLine("Process C Int:{0}", access.ReadInt32(501));
            access.Dispose();
        }
        mutex.ReleaseMutex();
        mmf.Dispose();
    }
    Console.Read();
}

但结果如下

流程A说：是的流程B说：错误流程C说：错误 Process A Int：2828841 过程B Int：11050 Process C Int：43

任何人都可以告诉我这个问题吗？

为什么结果处理A，B

不是41和42

Answer 1

查找此代码

// For Process B Read
accessor.Write(499, 41);
// For Process B Read
accessor.Write(503, 42);
// For Process C Read
accessor.Write(507, 43);
Console.WriteLine("Process A Int:{0}", access.ReadInt32(499));
Console.WriteLine("Process B Int:{0}", access.ReadInt32(503));
Console.WriteLine("Process C Int:{0}", access.ReadInt32(507));

然后结果是

处理A Int：41 过程B Int：42 Process C Int：43

或查找此代码

Console.WriteLine("Process A Int:{0}", access.ReadByte(499));
Console.WriteLine("Process B Int:{0}", access.ReadByte(500));
Console.WriteLine("Process C Int:{0}", access.ReadByte(501));

有相同的结果

感谢@Hans Passant

如何在C＃中使用MemoryMappedViewAccessor共享内存函数

1 个答案: