我在命令行上玩了一场双人棋。我有一个类,每种类型的棋子和董事会类。董事会类看起来像这样:
class Board
attr_accessor :board, :choice
def initialize
@board = Array.new(8){Array.new(8," ")}
@choice = choice
end
end
我的其他课程如下:
class Bishop
attr_accessor :x_position, :y_position, :piece, :color, :counter, :moves
def initialize(position,boolean)
@x_position = position[0]
@y_position = position[1]
@piece = boolean ? "♝" : "♗"
@color = boolean ? "white" : "black"
@counter = 0
@moves = [[+1,-1],
[+1,+1],
[-1,+1],
[-1,-1]]
end
我把我的作品添加到棋盘上:
@board[0][0] = Rook.new([0,0],false)
这些是我序列化和反序列化数据的方法:
def to_json
JSON.generate({board: @board})
end
def save_game(string)
File.open("saved.json", "w") do |game_file|
game_file.write(string)
end
end
def load_game
game_file = File.read("saved.json")
data = JSON.parse(game_file)
@board = data["board"]
end
保存后,saved.json文件如下所示:
{"board":[[" ","#<Knight:0x00000000e4fc28>","#<Bishop:0x00000000e4fa20>","#<Queen:0x00000000e4f890>","#<King:0x00000000e4f610>","#<Bishop:0x00000000e4f3e0>","#<Knight:0x00000000e4f278>","#<Rook:0x00000000e4e1c0>"],[" "," "," "," "," "," "," "," "],[" "," "," "," "," "," "," "," "],[" "," "," "," "," "," "," "," "],[" "," "," "," "," "," "," "," "],[" "," "," "," "," "," "," "," "],[" "," "," "," "," "," "," "," "],["#<Rook:0x00000000e4fd90>","#<Knight:0x00000000e4ed78>","#<Bishop:0x00000000e4eb70>","#<Queen:0x00000000e4ea08>","#<King:0x00000000e4e7b0>","#<Bishop:0x00000000e4e580>","#<Knight:0x00000000e4e3f0>"," "]]}
当我尝试加载数据时,显示该板的方法会抛出此错误:
0 1 2 3 4 5 6 7
+----+----+----+----+----+----+----+----+
0| /home/jacob/Desktop/chess/board.rb:30:in `block (2 levels) in display': undefined method `piece' for "#<Knight:0x00000000e4fc28>":String (NoMethodError)
from /home/jacob/Desktop/chess/board.rb:27:in `each'
from /home/jacob/Desktop/chess/board.rb:27:in `each_with_index'
from /home/jacob/Desktop/chess/board.rb:27:in `block in display'
from /home/jacob/Desktop/chess/board.rb:20:in `each'
from /home/jacob/Desktop/chess/board.rb:20:in `each_with_index'
看起来我的问题是对象以字符串形式返回?
我的显示方法:
def display
axis = 0
print " 0 1 2 3 4 5 6 7"
@board.each_with_index do |row,index|
print "\n"
@draw = " +----+----+----+----+----+----+----+----+"
puts @draw
print axis
axis +=1
if index.even?
row.each_with_index do|column,i|
if i.odd?
if column != " "
print "|"+" #{column.piece} ".bruno
else print "|"+" #{column} ".bruno
end
else
if column != " "
print "|"+" #{column.piece} "
else print "|"+" #{column} "
end
end
end
else
row.each_with_index do|column,j|
if j.even?
if column != " "
print "|"+" #{column.piece} ".bruno
else print "|"+" #{column} ".bruno
end
else
if column != " "
print "|"+" #{column.piece} "
else print "|"+" #{column} "
end
end
end
end
print "|"
end
print "\n"
print @draw
end
答案 0 :(得分:1)
不,问题是您的对象已保存为字符串。在这种情况下,反序列化工作正常。您必须明确指定游戏片段的json表示。像这样:
class Rook
def to_json(*)
{ name: 'rook', position: 'A1', status: 'in_game' }.to_json
end
end
pieces = [Rook.new]
pieces.to_json # => "[{\"name\":\"rook\",\"position\":\"A1\",\"status\":\"in_game\"}]"
JSON.parse(pieces.to_json) # => [{"name"=>"rook", "position"=>"A1", "status"=>"in_game"}]
在反序列化时,你必须做相反的事情。从纯粹的ruby哈希构造适当的游戏类,您可以从解析JSON文件中获得它。
或者,如果您实际上并不关心JSON并且只想创建某种形式的保存文件,那么Marshal
是您最好的朋友。无需重写任何内容。零摩擦。
pieces = [Rook.new]
Marshal.dump(pieces) # => "\x04\b[\x06o:\tRook\x00" # write this to a file
# restore it later
Marshal.load("\x04\b[\x06o:\tRook\x00") # => [#<Rook:0x007fb50f825570>]