Question

我正在尝试在特定级别的JSON树中学习搜索方法。我有以下JSON模板示例：

"Pair": {
    "Instrument_A": {
        "Segment A": {
            "default": {
                "value X": 1,
                "value Z": 2,
                "value Y": 3,

            }
        },
        "Segment B": {
            "default": {
                "value X": 1,
                "value Z": 2,
                "value Y": 3,

            }
        }
    },
    "Instrument_B": {
        "Segment A": {
            "not-default": {
                "value X": 1,
                "value Z": 2,
                "value Y": 3,

            }
        }
    }
}

我的目标是计算名称不等于＆＃34; 默认＆＃34;的所有数组，例如，您可以在工具B，Segment下的4级看到A，有一个名为＆＃34; not-default ＆＃34;

的对象

Answer 1

您可以使用json包解析json并遍历字典。

Python2：

import json
json_str = "..."
json_object = json.loads(json_str)
for pair_k, pair_v in json_object.iteritems():
    for inst_k, inst_v in pair_v.iteritems():
        for seg_k, seg_v in inst_v.iteritems():
            if not seg_v == "default"
                pass # do whatever you want - print, append to list, etc.

Python3：

import json
json_str = "..."
json_object = json.loads(json_str)
for pair_k, pair_v in json_object.items():
    for inst_k, inst_v in pair_v.items():
        for seg_k, seg_v in inst_v.items():
            if not seg_v == "default"
                pass # do whatever you want - print, append to list, etc.

Answer 2

count = Counter()

def count_keys(data):
    if isinstance(data, dict):
        for key, value in data.items():
            if key != 'default':
                count[key]+=1
            count_keys(data[key])

count_keys(data)
print(count)

打印

Counter({'value X': 3, 'value Z': 3, 'value Y': 3, 'Segment A': 2, 'Pair': 1,'Instrument_A': 1, 'Segment B': 1, 'Instrument_B': 1, 'not-default': 1})

如何使用Python在JSON树中搜索特定级别

2 个答案: