Question

e4 = prompt("Enter the five favorite sports", "hockey,football,basketball,tennis,golf");
e4 = e4.split(",")

for (var i = 0; i < e4.length; i++) {
    if (e4[i] == "football") {
        e4[i] = "soccer";
    }
} 
e5 = prompt("Enter extra sport", "formula 1");
e4.push(e5);

for (var i = 0; i < e4.length; i++) {
    e4[i] = e4[i].toUpperCase();
}
e4.sort();

这是我的代码行，可以像这样打印出来

["BASKETBALL", "FORMULA 1", "GOLF", "HOCKEY", "SOCCKER", "TENNIS]

然而，我想要打印出来的格式如下：

BASKETBALL
FORMULA 1
GOLF
HOCKEY
SOCCER
TENNIS

其他代码的新行将从这里开始。

我来自C ++，所以我意识到\n，但你会如何格式化它，所以它像上面那样缩进，并且每当它通过数组中的元素时创建新行？

Answer 1

您可以尝试以下内容：

e4 = prompt("Enter the five favorite sports", "hockey,football,basketball,tennis,golf");
e4 = e4.split(",");

for (var i = 0; i < e4.length; i++) {
	if (e4[i] == "football") {
		e4[i] = "soccer";
	}
}
e5 = prompt("Enter extra sport", "formula 1");
e4.push(e5);
e4.sort();

for (var i = 0; i < e4.length; i++) {
	e4[i] = e4[i].toUpperCase();
	if (i == e4.length) {
		e4[i] = "    " + e4[i];
	} else {
		e4[i] = "    " + e4[i] + "\n";
	}
}

console.log(e4.toString().replace(/,/g, ""));

Answer 2

IMO，这是一个完美的用例const initialState = { noteName: [] }; export default function(state = initialState, action) { switch (action.type) { case INPUT_VALUE: return { noteName: [...state.noteName, action.payload] }; default: return state; } }

在Array#join

中使用<br/>标记作为粘合剂

[].join

在循环中缩进并为我的数组创建新空间

2 个答案: