Question

编写JavaScript以提示用户输入奇数。首先，检查用户是否输入了有效的奇数。然后，您需要在控制台上打印一个由与用户输入的数字相同数量的*字符组成的十字架。

到目前为止，我的代码是这样的

我已编辑了我的代码以包含正确的方式

let num = prompt("Enter an odd number");
let star = "*";
let vertical = "";
let horizontal = star.repeat(num);

while (num%2 == 0) {
    console.log("User did not enter an odd number");
    num = prompt("Enter an odd number");
}
console.log("User's number is " +num);
let pos = +(Math.ceil(num/2));
// I need to divide the input number by 2 and round up
for (var h = 0; h < pos; h++){
    vertical += (" ")

}

for (var v = 0; v < pos; v++){
    vertical += vertical + "\n *"
}
vertical += "*"
console.log (vertical)

我可以在适当的时间内垂直播放，但我如何确保不重复*？

Answer 1

最初你正在分配

let vertical = "*";

将其更改为

let vertical = "";

试试这个

let num = prompt("Enter an odd number");
let star = "*";
let vertical = "";
let horizontal = star.repeat(num)

while (num%2 == 0) {
console.log("User did not enter an odd number");
num = prompt("Enter an odd number");
}
console.log("User's number is " +num);
let pos = +(Math.ceil(num/2));
// I need to divide the input number by 2 and round up
for (var h = 0; h < pos; h++){
vertical += (" ")

}
console.log(vertical)

Answer 2

你走在正确的轨道上。您需要在此处执行三个步骤。你需要像这样创建一个十字架（假设数字是13）：

   *
   *
   *
*******
   *
   *
   *

您需要创建一个星形的Math.floor(13/4)（来自3个）行，每个星形位于Math.floor(13/4)个空格之后。然后，您需要从位置0开始的一排Math.ceil(13/2)个星星。最后，您需要与该行之前相同数量的星星，因此您可以再次执行相同的操作。

使用你的代码，我会做这样的事情：

let num = prompt("Enter an odd number");

while (num%2 == 0) {
    console.log("User did not enter an odd number");
    num = prompt("Enter an odd number");
}
console.log("User's number is " +num);

let star = " ";
let pos = Math.floor(num/4);
let vertical = star.repeat(pos) + "*";

for (var i = 0; i < pos; i++) {
    console.log(vertical);
}

console.log("*".repeat(Math.ceil(num/2)));

for (var i = 0; i < pos; i++) {
    console.log(vertical);
}

在for循环中在字符串前面添加空格

2 个答案: