Question

我是Python的初学者，我正在尝试使用函数编写一个本质上是“算命先生”的程序。我在调用函数get_today（）时似乎遇到了一个问题，该函数被编写为从该用户的月中获取输入，并将其作为整数返回。

然而，当我调用该函数时，系统会提示我出现错误：

TypeError: get_today() missing 1 required positional argument: 'd'

我试过玩了一下，无法弄清楚这意味着什么。这是主要功能：

def main():

    print("Welcome to Madame Maxine's Fortune Palace. Here, we gaze deeply into your soul and find the secrets that only destiny has heretofore known!")
    print("")
    print("The power of my inner eye clouds my ability to keep track of mundane things like the date.")
    d = get_today()
    print("Numerology is vitally important to fortune telling.")
    b = get_birthday()

    if(d >=1 and d <= 9):
        print("One more question before we begin.")
        a = likes_spicy_food()
        print("I will now read your lifeline")
        read_lifeline(d,b,a)
    if(d >= 10 and d <= 19):
        print("I will now read your heartline.")
        read_heartline(d,b)
    if(d >= 20 and d <= 29):
        print("I need one last piece of information.")
        m = get_birthmonth()
        read_headline(b,m)

    if(d == 30 or d == 31):
        print("Today is a bad day for fortune telling.")

        print("These insights into your future are not to be enjoyed or dreaded, they simply come to pass.")
        print("Good day.")

main()

当调用第二个函数get_birthday（）时，可能会重复此问题，该函数会询问用户出生的那一天。

以下是get_today（）的代码段：

def get_today():

        x = int(input("Tell me, what day of the month is it today:"))

        return x

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Answer 1

当我按原样运行此代码时，它不会给我你的错误。但是，当我在d = get_today()下使用d = get_today(d)作为main运行此代码时，我会收到您收到的错误。

当你调用一个函数时，括号之间的内容是传递给函数的内容。由于您尚未分配d，因此无法将其传入。此外，您的函数不需要传入变量，因为它只是用户输入。

试试这个：

def main():
    #code
    d = get_today()
    #more code

def get_today()
    #the function with return statement

main()

尝试调用函数时出错

1 个答案: