我有数据库,他们可以在图像中输入其中一个字段。图像保存在手机上,URI保存在数据库中。
当用户决定不为某个项目添加图像时,我遇到了麻烦。
我正在尝试编写if / else语句,其中“if”条件检查游标的image列是否为null。我只是无法弄清楚在if条件中输入什么内容。
这是我正在使用的一些代码。基本上我想这样做,如果光标的COLUMN_WINE_IMAGE为空,只需要祝酒。如果它不为空,则设置图像。
//This section turns the database's image URI stored in this cursor into a bitmap, and then sets the ImageView.
Bitmap bitmap = null;
try {
if (............){
Toast.makeText(this, "No image was taken for this item. (TOAST IS JUST TESTING PURPOSES)", Toast.LENGTH_SHORT).show();
}else{
bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.parse(cursor.getString(cursor.getColumnIndexOrThrow(WineContract.WineEntry.COLUMN_WINE_IMAGE))));
mFullImage.setImageBitmap(bitmap);
}
} catch (IOException e) {
e.printStackTrace();
}
以下是我尝试过的其中一件事没有成功的例子:
if (Uri.parse(cursor.getString(cursor.getColumnIndexOrThrow(WineContract.WineEntry.COLUMN_WINE_IMAGE))).equals(null)){
//This returns error: java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.jeremy.sqlwine/com.example.jeremy.sqlwine.DetailsActivity}: java.lang.NullPointerException: uriString
答案 0 :(得分:1)
以单独的方法检索列值。然后在使用之前检查返回值。
尝试这样的事情:
private String checkDatabaseValue(Cursor cursor){
String result = null;
try{
//This can throw an error if the column is not found
int index = cursor.getColumnIndexOrThrow(WineContract.WineEntry.COLUMN_WINE_IMAGE);
result = cursor.getString(index).trim();
}
catch(Exception ex){
// determine what threw the error and handle appropriately
Log.e(TAG, ex.getMessage());
}
return result;
}
然后在这里使用它:
Bitmap bitmap = null;
try {
// I'm assuming you have the cursor from somewhere!!
String imageFile = checkDatabaseValue(cursor);
if (imageFile == null){
Toast.makeText(this, "No image was taken for this item. (TOAST IS JUST TESTING PURPOSES)", Toast.LENGTH_SHORT).show();
return;
}
if(!imageFile.isEmpty()){
bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.parse(imageFile));
mFullImage.setImageBitmap(bitmap);
else{
Toast.makeText(this, "Empty String. (TOAST IS JUST TESTING PURPOSES)", Toast.LENGTH_SHORT).show();
}
} catch (IOException e) {
e.printStackTrace();
}
答案 1 :(得分:0)
改为使用:
if(cursor.getColumnIndexOrThrow(WineContract.WineEntry.COLUMN_WINE_IMAGE) == null)
更新:
cursor.isNull(cursor.getColumnIndexOrThrow(WineContract.WineEntry.COLUMN_WINE_IMAGE))